Chap3-多表查询

Posted 2020-11-27 zxdzxd

Chp3 复杂查询

key point：

数据分页

子查询

表连接

 

--分页查询练习

--1.查询工资最高的3名员工信息

select * from (select * from employees order by SALARY desc) where rownum <= 3;

--2.查询工资排名第5到第10的员工信息

select * from (select e.*,rownum r from employees e order by salary desc)where r between 5 and 10;

--3.查询first_name是以大写D开头的第3到第5个员工信息

select * from (select e.*,rownum r from employees e where first_name like ‘D%‘)where r between 3 and 5 ;

 

--子查询练习

--1.显示工资比’Allan’(first_name)高的所有员工的姓名和工资

select *from employees where salary > (select salary from employees where first_name = ‘Allan‘);

--2.显示与’Allan’(first_name)从事相同工作的员工的详细信息

select * from employees where job_id = (select job_id from employees where first_name = ‘Allan‘);

--3.查询工资大于本部门平均工资的员工基本信息

 

--4.显示与30号部门first_name为’Guy’员工工资相同的员工姓名和工资

select * from employees where department_id=30 and salary=(select salary from employees where first_name=‘Guy‘);

--5.查询所有工资高于平均工资(平均工资包括所有员工)的销售人员(‘SA_REP‘)

select *from employees where job_id=‘SA_REP‘ and salary > (select avg(salary) from employees) ;

--6.查询各个职位员工工资大于平均工资(平均工资包括所有员工)的人数和员工职位

select job_id,count(*) from employees where salary >(select avg(salary) from employees) group by job_id;

--7.查询各个职位员工工资大于平均工资(平均工资包括所有员工)的员工

 

 

--表连接查询练习

--1.查询在研发部(‘IT‘)工作员工的编号，姓名，工作部门，工作所在地

SELECT e.employee_id, e.first_name, d.department_name, l.street_address FROM employees e

LEFT JOIN departments d ON e.department_id = d.department_id

LEFT JOIN locations l ON d.location_id = l.location_id

WHERE d.department_name LIKE ‘IT‘;

--2.查询各个部门的名称和员工人数

SELECT e.department_id, d.department_name, COUNT(1) as 员工人数 FROM employees e

LEFT JOIN departments d ON e.department_id = d.department_id

GROUP BY e.department_id

--3.查询工资相同的员工的工资和姓名

SELECT e.employee_id, e2.employee_id, e.first_name, e2.first_name, e.salary FROM employees e

LEFT JOIN employees e2 ON e.salary = e2.salary

WHERE e.employee_id < e2.employee_id

ORDER BY e.salary

--4.显示10号部门的经理和20号部门的所有职员的详细信息

SELECT e.employee_id, e.manager_id, e.department_id FROM employees e

WHERE e.department_id = 20

OR e.employee_id = (SELECT e2.manager_id FROM employees e2 WHERE e2.department_id =10)

--5.查询员工的基本信息，附加其上级的姓名

SELECT e.employee_id, e.first_name, e.manager_id, e2.employee_id, e2.first_name FROM employees e

LEFT JOIN employees e2 ON e.manager_id = e2.employee_id

--6.求入职日期相同（年月日相同）的员工(考察知识点:自连接)

SELECT e.employee_id, e2.employee_id, e.hire_date, e2.hire_date FROM employees e

LEFT JOIN employees e2 ON e.hire_date = e2.hire_date

WHERE e.employee_id<e2.employee_id

ORDER BY e.hire_date;

--7.显示各个部门经理的基本工资

--第一步 查询各个部门的经理编号 --tb1

select * from departments d where d.manager_id is not null ;

--第二步 员工表与 tb1创建连接

select e.employee_id, d.department_id,d.manager_id, e.salary FROM employees e

INNER JOIN departments d ON e.employee_id = d.manager_id

ORDER BY d.department_id