《剑指offer》第二十七题:二叉树的镜像
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// 面试题27:二叉树的镜像 // 题目:请完成一个函数,输入一个二叉树,该函数输出它的镜像。 #include <cstdio> #include "BinaryTree.h" #include <stack> void MirrorRecursively(BinaryTreeNode* pNode) //自底向上 { if (pNode == nullptr || (pNode->m_pLeft == nullptr && pNode->m_pRight == nullptr)) return; //交换父节点的两个子节点 BinaryTreeNode* pTemp = pNode->m_pLeft; pNode->m_pLeft = pNode->m_pRight; pNode->m_pRight = pTemp; if (pNode->m_pLeft) //交换左子节点的子节点 MirrorRecursively(pNode->m_pLeft); if (pNode->m_pRight) //交换右子节点的子节点 MirrorRecursively(pNode->m_pRight); } void MirrorIteratively(BinaryTreeNode* pRoot) //自顶向下 { if (pRoot == nullptr) return; std::stack<BinaryTreeNode*> treeNodeStack; //存放未交换的根节点 treeNodeStack.push(pRoot); while (treeNodeStack.size() > 0) { BinaryTreeNode* pNode = treeNodeStack.top(); treeNodeStack.pop(); //交换父节点的两个子节点 BinaryTreeNode* pTemp = pNode->m_pLeft; pNode->m_pLeft = pNode->m_pRight; pNode->m_pRight = pTemp; if (pNode->m_pLeft) treeNodeStack.push(pNode->m_pLeft); if (pNode->m_pRight) treeNodeStack.push(pNode->m_pRight); } }
// ====================测试代码==================== // 测试完全二叉树:除了叶子节点,其他节点都有两个子节点 // 8 // 6 10 // 5 7 9 11 void Test1() { printf("=====Test1 starts:===== "); BinaryTreeNode* pNode8 = CreateBinaryTreeNode(8); BinaryTreeNode* pNode6 = CreateBinaryTreeNode(6); BinaryTreeNode* pNode10 = CreateBinaryTreeNode(10); BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); BinaryTreeNode* pNode7 = CreateBinaryTreeNode(7); BinaryTreeNode* pNode9 = CreateBinaryTreeNode(9); BinaryTreeNode* pNode11 = CreateBinaryTreeNode(11); ConnectTreeNodes(pNode8, pNode6, pNode10); ConnectTreeNodes(pNode6, pNode5, pNode7); ConnectTreeNodes(pNode10, pNode9, pNode11); PrintTree(pNode8); printf("=====Test1: MirrorRecursively===== "); MirrorRecursively(pNode8); PrintTree(pNode8); printf("=====Test1: MirrorIteratively===== "); MirrorIteratively(pNode8); PrintTree(pNode8); DestroyTree(pNode8); } // 测试二叉树:出叶子结点之外,左右的结点都有且只有一个左子结点 // 8 // 7 // 6 // 5 // 4 void Test2() { printf("=====Test2 starts:===== "); BinaryTreeNode* pNode8 = CreateBinaryTreeNode(8); BinaryTreeNode* pNode7 = CreateBinaryTreeNode(7); BinaryTreeNode* pNode6 = CreateBinaryTreeNode(6); BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); BinaryTreeNode* pNode4 = CreateBinaryTreeNode(4); ConnectTreeNodes(pNode8, pNode7, nullptr); ConnectTreeNodes(pNode7, pNode6, nullptr); ConnectTreeNodes(pNode6, pNode5, nullptr); ConnectTreeNodes(pNode5, pNode4, nullptr); PrintTree(pNode8); printf("=====Test2: MirrorRecursively===== "); MirrorRecursively(pNode8); PrintTree(pNode8); printf("=====Test2: MirrorIteratively===== "); MirrorIteratively(pNode8); PrintTree(pNode8); DestroyTree(pNode8); } // 测试二叉树:出叶子结点之外,左右的结点都有且只有一个右子结点 // 8 // 7 // 6 // 5 // 4 void Test3() { printf("=====Test3 starts:===== "); BinaryTreeNode* pNode8 = CreateBinaryTreeNode(8); BinaryTreeNode* pNode7 = CreateBinaryTreeNode(7); BinaryTreeNode* pNode6 = CreateBinaryTreeNode(6); BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); BinaryTreeNode* pNode4 = CreateBinaryTreeNode(4); ConnectTreeNodes(pNode8, nullptr, pNode7); ConnectTreeNodes(pNode7, nullptr, pNode6); ConnectTreeNodes(pNode6, nullptr, pNode5); ConnectTreeNodes(pNode5, nullptr, pNode4); PrintTree(pNode8); printf("=====Test3: MirrorRecursively===== "); MirrorRecursively(pNode8); PrintTree(pNode8); printf("=====Test3: MirrorIteratively===== "); MirrorIteratively(pNode8); PrintTree(pNode8); DestroyTree(pNode8); } // 测试空二叉树:根结点为空指针 void Test4() { printf("=====Test4 starts:===== "); BinaryTreeNode* pNode = nullptr; PrintTree(pNode); printf("=====Test4: MirrorRecursively===== "); MirrorRecursively(pNode); PrintTree(pNode); printf("=====Test4: MirrorIteratively===== "); MirrorIteratively(pNode); PrintTree(pNode); } // 测试只有一个结点的二叉树 void Test5() { printf("=====Test5 starts:===== "); BinaryTreeNode* pNode8 = CreateBinaryTreeNode(8); PrintTree(pNode8); printf("=====Test4: MirrorRecursively===== "); MirrorRecursively(pNode8); PrintTree(pNode8); printf("=====Test4: MirrorIteratively===== "); MirrorIteratively(pNode8); PrintTree(pNode8); } int main(int argc, char* argv[]) { Test1(); Test2(); Test3(); Test4(); Test5(); return 0; }
分析:基于循环的方法很巧妙。
/* struct TreeNode { int val; struct TreeNode *left; struct TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) { } };*/ class Solution { public: void Mirror(TreeNode *pRoot) { if (pRoot == nullptr || (pRoot->left == nullptr && pRoot->right == nullptr)) return; TreeNode* treeTemp = pRoot->right; pRoot->right = pRoot->left; pRoot->left = treeTemp; if (pRoot->left) Mirror(pRoot->left); if (pRoot->right) Mirror(pRoot->right); } };
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