P1001 A+B Format

Posted 2020-11-25 daker-code

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1001 A+B Format (20分)

 

Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where −10?^6??≤a,b≤10?⁶. The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

 

Sample Output:

-999,991

　　这道题的意思是，将A+B 两个数相加，且 A B两个数 限制为 −10?^6??≤a ,b≤10?⁶ ，然后按照国际标准给数字填上，我偷了个懒， A， B整型输入， 和存储在字符串里，然后%c一个个输出

这里需要注意几个输出点：

1. 　　最后一位，不需要判断
2. 　　如果和小于0，那么需要跳过‘-’
3. 　　注意数组大小，记得考虑进位和‘’以及‘-’

AC代码如下：

−10?6??≤a,b≤10?6#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(void)
{
    char str[9];
    int A, B;

    scanf("%d %d", &A, &B);
    sprintf(str, "%d", (A + B));
    int len = strlen(str);

    for (int i = 0; i < len; i++)
    {
        printf("%c", str[i]);
        if (len - 1 == i || ‘-‘ == str[i])
        {
            continue;
        }
        if (0 == (len - 1 - i) % 3)
        {
            printf(",");
        }
    }

    return 0;
}