笔试题--有3个线程A/B/C,其中AB个线程轮流打印1-100 中间如果是10的倍数,则由C线程打印;
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* 评测题目: 有3个线程A/B/C,其中A、B个线程轮流打印1-100 中间如果是10的倍数,则由C线程打印; * 要求在控制台输入如下内容: * 线程A:1 * 线程B:2 * 线程A:3 * …… * 线程C:10 * …… * 线程?:100
/** * 多个线程共享这一个sequence数据 */ private static int sequence = 1; private static final int SEQUENCE_END = 100; private Integer id; private ReentrantLock lock; private Condition[] conditions; private String name = ""; private ThreadPrintService() { } private ThreadPrintService(String name, Integer id, ReentrantLock lock, Condition[] conditions) { this.id = id; this.lock = lock; this.conditions = conditions; this.name = name; } @Override public void run() { while (sequence >= 0 && sequence <= SEQUENCE_END) { lock.lock(); try { //对序号取模,如果不等于当前线程的id,则先唤醒其他线程,然后当前线程进入等待状态 while (sequence % 2 != id) { if (sequence % 10 == 0) { break; } conditions[(id + 1) % conditions.length].signal(); conditions[(id + 2) % conditions.length].signal(); conditions[id].await(); } System.out.println(name + " : " + sequence); //序号加1 sequence = sequence + 1; //唤醒当前线程的下一个线程 conditions[(id + 2) % conditions.length].signal(); //当前线程进入等待状态 conditions[id].await(); } catch (InterruptedException e) { e.printStackTrace(); } finally { //将释放锁的操作放到finally代码块中,保证锁一定会释放 lock.unlock(); } } //数字打印完毕,线程结束前唤醒其余的线程,让其他线程也可以结束 end(); } private void end() { lock.lock(); conditions[(id + 1) % conditions.length].signal(); conditions[(id + 2) % conditions.length].signal(); lock.unlock(); } public void startThread() { int threadCount = 3; String name = ""; ReentrantLock lock = new ReentrantLock(); Condition[] conditions = new Condition[threadCount]; for (int i = 0; i < threadCount; i++) { conditions[i] = lock.newCondition(); } ThreadPrintService[] printNumbers = new ThreadPrintService[threadCount]; for (int i = 0; i < threadCount; i++) { switch (i) { case 0: name = "B"; break; case 1: name = "A"; break; case 2: name = "C"; break; } ThreadPrintService p = new ThreadPrintService(name, i, lock, conditions); printNumbers[i] = p; } for (ThreadPrintService printNumber : printNumbers) { new Thread(printNumber).start(); } }
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