C++ jsoncpp 输出名称和值

Posted 2023-05-18

用jsoncpp解析完成后，我想在得到值的同时得到该值对应的名称
如下：
"name":"json"
“age”:"18"
我想得到“name”、"age"

参考技术A Json::Reader arrayReader;
Json::Value arrayValue;
arrayReader.parse(jsonData, arrayValue);
Json::Value::Members arrayMember = arrayValue.getMemberNames(); //ayyayMember是成员名称的集合，即name,age;
for(Json::Value::Members::iterator iter = arrayMember.begin(); iter != arrayMember.end(); ++iter) //遍历json成员

string member_name= *iter;
string value_str = arrayValue[member_name].asString();
cout<<member_name<<":"<<value_str<<endl;
参考技术B 你是根据什么区取值的 那个就是你要的名称

输出javascript对象中属性的名称和值

The code below will loop through the properties in an object and alert a string. myObject is in JSON notation. The "for ( x in y)" construct does not work if the Prototype.js library is included on the page

// output the name and value of all the objects properties
var s = "";
 
for (var property in myObject)
{
s = s + "
 "+property +": " + myObject[property] ;
}
 
alert(s);