HttpClient 上传文件

Posted 2020-11-23 for_oscar

/// <summary>
/// 发送post请求
/// </summary>
/// <param name="filePath">文件路径</param>
/// <param name="pID">患者ID</param>
/// <returns></returns>
public static string HttpPostRequst(string filePath, string pID)
{
string data = string.Empty;
try
{
string url = ConfigurationManager.AppSettings["WebURLPOST"];
var fileName = Path.GetFileName(filePath);
using (var fClient = new HttpClient())
{
MultipartFormDataContent content = new MultipartFormDataContent();

FileStream fileStream = File.Open(filePath, FileMode.Open);
StreamContent streamContent = new StreamContent(fileStream);
streamContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data");
streamContent.Headers.ContentDisposition.Name = "ecg_file";
streamContent.Headers.ContentDisposition.FileName = fileName;
streamContent.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");

HttpContent strParam = new StringContent("891164e528c4450485f356d662466e5c");
strParam.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data");
strParam.Headers.ContentDisposition.Name = "exam_id";

content.Add(strParam);
content.Add(streamContent);

data = fClient.PostAsync(new Uri(url), content).Result.Content.ReadAsStringAsync().Result;
streamContent.Dispose();
fileStream.Dispose();

}
}
catch (Exception ex)
{
CommonLog.WriteECGLog("发送文件流出错：" + ex.Message + " " + " ", "upload");
}
return data;
}