消除左递归
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1.将以下文法消除左递归,分析符号串 i*i+i 。
并分别求FIRST集、FOLLOW集,和SELECT集
E -> E+T | T
T -> T*F | F
F -> (E) | i
解:
消除左递归:
E ->TE`
E` ->+TE`|ε
T ->FT `
T `->*FT `|ε
F ->i|(E)
FIRST集:
FIRST(TE`)={T}
FIRST(+TE`)={+,ε}
FIRST(ε)={ε}
FIRST(FT `)={F}
FIRST(*FT `)={*}
FIRST((E))={T}
FIRST(i)={i}
FOLLOW集:
FOLLOW(E)={}
FOLLOW(E`)={#}
FOLLOW(T)={E`}
FOLLOW(T`)={#}
FOLLOW(F)={#}
SELECT集:
SELECT(E→TE`)=FIRST(TE`)={T}
SELECT(E`→+TE`)=FIRST(+TE`)={+}
SELECT(E`→ε)=(FIRST(ε)-{ε})∪FOLLOW(E`)={)}
SELECT(T→FT`)=FIRST(FT`)={F}
SELECT(T`→*FT`)=FIRST(*FT`)={*}
SELECT(T`→ε)=(FIRST(ε)-{ε})∪FOLLOW(T`)={#}
SELECT(F→(E))=FIRST((E))={(}
SELECT(F→i)=FIRST(i)={i}
分析符号串i*i+i
2.P101练习7(2)(3)文法改写,并分别求FIRST集、FOLLOW集,和SELECT集
A → aABe|a
B → Bb|d
提取左公因子:
A→aA`
A`→ABe|ε
消除左递归:
B→dB`
B`→bB`|ε
FIRST集:
FIRST(aA`)={a}
FIRST(ABe)={A}
FIRST(ε)={ε}
FIRST(dB`)={d}
FIRST(bB`)={b}
FOLLOW集:
FOLLOW(A)={Be}
FOLLOW(A`)={#}
FOLLOW(B)={e}
FOLLOW(B`)={#}
SELECT集:
SELECT(A→aA`)=FIRST(aA`)={a}
SELECT(A`→ABe)=FIRST(ABe)={A}
SELECT(A`→ε)=(FIRST(ε)-{ε})∪FOLLOW(A`)={#}
SELECT(B→dB`)=FIRST(dB`)={d}
SELECT(B`→bB`)=FIRST(bB`)={b}
SELECT(B`→ε)=(FIRST(ε)-{ε})∪FOLLOW(B`)={#}
S → Aa|b
A → SB
B → ab
代入:
S→SBa|b
消除左递归:
S →bS`
S`→BaS`|ε
B→ab
FIRST集:
FIRST(SBa)={S}
FIRST(b)={b}
FIRST(bS`)={b}
FIRST(BaS)={B}
FIRST(ε)={ε}
FIRST(ab)={ab}
FOLLOW集:
FOLLOW(S)={B}
FOLLOW(S`)={#}
FOLLOW(B)={a}
SELECT集:
SELECT(S→SBa)=FIRST(SBa)={S}
SELECT(S→b)=FIRST(b)={b}
SELECT(S→bS`)=FIRST(bS`)={b}
SELECT(S`→BaS`)=FIRST(BaS`)={B}
SELECT(S`→ε)=(FIRST(ε)-{ε})∪FOLLOW(S`)={#}
SELECT(B→ab)=FIRST(ab)={a}
课堂练习:
求以下文法的FIRST集、FOLLOW集和SELECT集。
S->Ap S->Ap
A->a |ε =>ap
A->cA =>p
A->aA =>cAp
=>aAp
FIRST(a)={a}
FIRST(ε)={ε}
FIRST(cA)={c}
FIRST(aA)={a}
FIRST(Ap)={a,c,p}
FOLLOW(S)={#}
FOLLOW(A)= {p}
SELECT(S→Ap)=FIEST(Ap)={A}
SELECT(A→a)=FIRST(a)={a}
SELECT(A→ε)=(FIRST(ε)-{ε})∪FOLLOW(A)={p}
SELECT(A→cA)=FIRST(cA)={c}
SELECT(A→aA)=FIRST(aA)={a}
S->Ap S->Ap S->Bq
S->Bq =>ap =>bq
A->a =>cAp =>dBq
A->cA
B->b
B->dB
FIRST(a)={a}
FIRST(cA)={c}
FIRST(b)={b}
FIRST(dB)={d}
FIRST(Ap)={a,c}
FIRST(Bq)={b,d}
FOLLOW(S)={#}
FOLLOW(A)={p}
FOLLOW(B)={q}
SELECT(S→Ap)=FIEST(Ap)={A}
SELECT(S→Bq)=FIRST(a)={a}
SELECT(A→a)=FIRST(a)={a}
SELECT(A→cA)=FIRST(cA)={c}
SELECT(B→b)=FIRST(b)={b}
SELECT(B→dB)=FIRST(dB)={d}
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