xpath
Posted bensonchang
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了xpath相关的知识,希望对你有一定的参考价值。
from scrapy.http import HtmlResponse html = """<!DOCTYPE html> <html> <head lang="en"> <meta charset="UTF-8"> <title></title> </head> <body> <ul> <li class="item-"><a id=‘i1‘ href="link.html">first item</a></li> <li class="item-0"><a id=‘i2‘ href="llink.html">first item</a></li> <li class="item-1"><a href="llink2.html">second item<span>vv</span></a></li> </ul> <div><a href="llink2.html">second item</a></div> </body> </html> """ response = HtmlResponse(url = ‘http://example.com‘ , body = html,encoding = ‘utf-8‘ ) # hxs = HtmlXPathSelector(response) # print(hxs) # hxs = Selector(response=response).xpath(‘//a‘) # print(hxs) # hxs = Selector(response=response).xpath(‘//a[2]‘) # print(hxs) # hxs = Selector(response=response).xpath(‘//a[@id]‘) # print(hxs) # hxs = Selector(response=response).xpath(‘//a[@id="i1"]‘) # print(hxs) # hxs = Selector(response=response).xpath(‘//a[@href="link.html"][@id="i1"]‘) # print(hxs) # hxs = Selector(response=response).xpath(‘//a[contains(@href, "link")]‘) # print(hxs) # hxs = Selector(response=response).xpath(‘//a[starts-with(@href, "link")]‘) # print(hxs) # hxs = Selector(response=response).xpath(‘//a[re:test(@id, "id+")]‘) # print(hxs) # hxs = Selector(response=response).xpath(‘//a[re:test(@id, "id+")]/text()‘).extract() # print(hxs) # hxs = Selector(response=response).xpath(‘//a[re:test(@id, "id+")]/@href‘).extract() # print(hxs) # hxs = Selector(response=response).xpath(‘/html/body/ul/li/a/@href‘).extract() # print(hxs) # hxs = Selector(response=response).xpath(‘//body/ul/li/a/@href‘).extract_first() # print(hxs) # ul_list = Selector(response=response).xpath(‘//body/ul/li‘) # for item in ul_list: # v = item.xpath(‘./a/span‘) # # 或 # # v = item.xpath(‘a/span‘) # # 或 # # v = item.xpath(‘*/a/span‘) # print(v) |
以上是关于xpath的主要内容,如果未能解决你的问题,请参考以下文章