数字金字塔

Posted 2020-11-20 wang102030

num = eval(input("请输入一个整数："))
for i in range(1, num + 1):
    for j in range(num-i, 0, -1):
        print(" ", end="	")
    for j in range(i, 1, -1):
        print(j, end="	")
    for j in range(1, i+1):
        print(j, end="	")
    print(" ")

row = int(input("请输入行数："))
num = 1
sum = 0
for i in range(1, row + 1):
    for j in range(row - i, 0, -1):
        print(" ", end="	")

    for j in range(1, i + 1):
        print(num, end="	")
        num *= 2
        sum = num
    num = 1
    sum //= 2
    for j in range(2, i + 1):
        print(sum//2, end="	")
        sum //= 2

    print("")

 

pattern = input("请输入你要选择的模式：")
while True:
    if pattern == "A":
        row = eval(input("请输入行数："))
        for i in range(1, row + 1):
            for j in range(1, i+1):
                print(j, end=" ")
            print("")

    elif pattern == "B":
        row = eval(input("请输入行数："))
        for i in range(1, row + 1):
            for j in range(1, row - i + 2):
                print(j, end=" ")
            print("")

    elif pattern == "C":
        row = eval(input("请输入行数："))
        for i in range(1, row + 1):
            for j in range(row - i, 0, -1):
                print(" ", end=" ")
            for j in range(i, 0, -1):
                print(j, end=" ")
            print("")

    elif pattern == "D":
        row = eval(input("请输入行数："))
        for i in range(1, row + 1):
            for j in range(1, i):
                print(" ", end=" ")
            for j in range(1, row - i + 2 ):
                print(j, end=" ")
            print("")

    elif pattern == "退出":
        break
    else:
        pattern = input("输入错误,请从新输入")