URL 通过Get方式传递数组参数

Posted 2020-11-19 caihemm

URL 通过Get方式传递数组参数

方法1：

?id=1&id=2&id=3

后台获取时，只需要reqeust.getParameterValues("id") 获取String数组。

 

 

http协议的要求

解析参数时,相同的key会覆盖前一个,
如果带[]会当成一维数组来处理,就不会覆盖了

 

直接可以url =url+"?str1="+arrayP[0]+"&str2="+arrayP[1];

 

 

Generally, when the target server uses a strong typed programming language like Java (Servlet), then you can just send them as multiple parameters with the same name. The API usually offers a dedicated method to obtain multiple parameter values as an array.

foo=value1&foo=value2&foo=value3

String[] foo = request.getParameterValues("foo"); // [value1, value2, value3]

The request.getParameter("foo") will also work on it, but it‘ll return only the first value.

String foo = request.getParameter("foo"); // value1

And, when the target server uses a weak typed language like php or RoR, then you need to suffix the parameter name with braces [] in order to trigger the language to return an array of values instead of a single value.

foo[]=value1&foo[]=value2&foo[]=value3

$foo = $_GET["foo"]; // [value1, value2, value3]
echo is_array($foo); // true

In case you still use foo=value1&foo=value2&foo=value3, then it‘ll return only the first value.

$foo = $_GET["foo"]; // value1
echo is_array($foo); // false

Do note that when you send foo[]=value1&foo[]=value2&foo[]=value3 to a Java Servlet, then you can still obtain them, but you‘d need to use the exact parameter name including the braces.

String[] foo = request.getParameterValues("foo[]"); // [value1, value2, value3]