请问浏览器为啥上传文件跳转页面是空白?
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应该是被恶意插件篡改了浏览器程序,使之不能正常运行。还有可能就是杀毒软件的正常程序被木马破损了。再者,前方服务器出现问题,源软件在修改某些内容。建议使用360安全卫士或者金山定期杀毒,使电脑保持一个良好的运行环境。若杀毒后仍然出现所述的状况,你就把它卸载了,重新安装一个浏览器。切记不能随意改动浏览器的各项数据内容,否则又会出现上述状况。祝你上网愉快,希望有所帮助。 参考技术A 浏览器或插件有问题 也可能是此页面内容被某些拦截软件当成广告拦截掉了.为啥我的php脚本上传应该是图像的空白文件
【中文标题】为啥我的php脚本上传应该是图像的空白文件【英文标题】:why is my php script uploading blank files which should be images为什么我的php脚本上传应该是图像的空白文件 【发布时间】:2014-03-31 20:01:17 【问题描述】:我使用的是直接从书中获得的 php 脚本,没有错误。它应该可以工作...当我使用我的 php 表单上传 jpg 文件时,该文件会进入我的上传文件夹,但它没有类型,它是一个空白文件。当我查看文件的属性时,它只是说文件。我正在使用的 php 脚本不使用 mime 类型来识别正在上传的文件类型。但是根据论坛,这门课程的其他学生似乎没有这个问题。会不会是windows 8?我上传文件夹的权限似乎很好。有什么想法吗?
这里是代码..
<?php # Script 19.2 - add_print.php
// This page allows the administrator to add a print (product).
require ('../mysqli_connect.php');
if ($_SERVER['REQUEST_METHOD'] == 'POST') // Handle the form.
// Validate the incoming data...
$errors = array();
// Check for a print name:
if (!empty($_POST['print_name']))
$pn = trim($_POST['print_name']);
else
$errors[] = 'Please enter the print\'s name!';
// Check for an image:
if (is_uploaded_file ($_FILES['image']['tmp_name']))
// Create a temporary file name:
$temp = '../../uploads/' . md5($_FILES['image']['name']);
// Move the file over:
if (move_uploaded_file($_FILES['image']['tmp_name'], $temp))
echo '<p>The file has been uploaded!</p>';
// Set the $i variable to the image's name:
$i = $_FILES['image']['name'];
else // Couldn't move the file over.
$errors[] = 'The file could not be moved.';
$temp = $_FILES['image']['tmp_name'];
else // No uploaded file.
$errors[] = 'No file was uploaded.';
$temp = NULL;
// Check for a size (not required):
$s = (!empty($_POST['size'])) ? trim($_POST['size']) : NULL;
// Check for a price:
if (is_numeric($_POST['price']) && ($_POST['price'] > 0))
$p = (float) $_POST['price'];
else
$errors[] = 'Please enter the print\'s price!';
// Check for a description (not required):
$d = (!empty($_POST['description'])) ? trim($_POST['description']) : NULL;
// Validate the artist...
if ( isset($_POST['artist']) && filter_var($_POST['artist'], FILTER_VALIDATE_INT, array('min_range' => 1)) )
$a = $_POST['artist'];
else // No artist selected.
$errors[] = 'Please select the print\'s artist!';
if (empty($errors)) // If everything's OK.
// Add the print to the database:
$q = 'INSERT INTO prints (artist_id, print_name, price, size, description, image_name) VALUES (?, ?, ?, ?, ?, ?)';
$stmt = mysqli_prepare($dbc, $q);
mysqli_stmt_bind_param($stmt, 'isdsss', $a, $pn, $p, $s, $d, $i);
mysqli_stmt_execute($stmt);
// Check the results...
if (mysqli_stmt_affected_rows($stmt) == 1)
// Print a message:
echo '<p>The print has been added.</p>';
// Rename the image:
$id = mysqli_stmt_insert_id($stmt); // Get the print ID.
rename ($temp, "../../uploads/$id");
// Clear $_POST:
$_POST = array();
else // Error!
echo '<p style="font-weight: bold; color: #C00">Your submission could not be processed due to a system error.</p>';
mysqli_stmt_close($stmt);
// End of $errors IF.
// Delete the uploaded file if it still exists:
if ( isset($temp) && file_exists ($temp) && is_file($temp) )
unlink ($temp);
// End of the submission IF.
// Check for any errors and print them:
if ( !empty($errors) && is_array($errors) )
echo '<h1>Error!</h1>
<p style="font-weight: bold; color: #C00">The following error(s) occurred:<br />';
foreach ($errors as $msg)
echo " - $msg<br />\n";
echo 'Please reselect the print image and try again.</p>';
// Display the form...
?>
<h1>Add a Print</h1>
<form enctype="multipart/form-data" action="add_print.php" method="post">
<input type="hidden" name="MAX_FILE_SIZE" value="524288" />
<fieldset><legend>Fill out the form to add a print to the catalog:</legend>
<p><b>Print Name:</b> <input type="text" name="print_name" size="30" maxlength="60" value="<?php if (isset($_POST['print_name'])) echo htmlspecialchars($_POST['print_name']); ?>" /></p>
<p><b>Image:</b> <input type="file" name="image" /></p>
<p><b>Artist:</b>
<select name="artist"><option>Select One</option>
<?php // Retrieve all the artists and add to the pull-down menu.
$q = "SELECT artist_id, CONCAT_WS(' ', first_name, middle_name, last_name) FROM artists ORDER BY last_name, first_name ASC";
$r = mysqli_query ($dbc, $q);
if (mysqli_num_rows($r) > 0)
while ($row = mysqli_fetch_array ($r, MYSQLI_NUM))
echo "<option value=\"$row[0]\"";
// Check for stickyness:
if (isset($_POST['artist']) && ($_POST['artist'] == $row[0]) ) echo ' selected="selected"';
echo ">$row[1]</option>\n";
else
echo '<option>Please add a new artist first.</option>';
mysqli_close($dbc); // Close the database connection.
?>
</select></p>
<p><b>Price:</b> <input type="text" name="price" size="10" maxlength="10" value="<?php if (isset($_POST['price'])) echo $_POST['price']; ?>" /> <small>Do not include the dollar sign or commas.</small></p>
<p><b>Size:</b> <input type="text" name="size" size="30" maxlength="60" value="<?php if (isset($_POST['size'])) echo htmlspecialchars($_POST['size']); ?>" /> (optional)</p>
<p><b>Description:</b> <textarea name="description" cols="40" rows="5"><?php if (isset($_POST['description'])) echo $_POST['description']; ?></textarea> (optional)</p>
</fieldset>
<div align="center"><input type="submit" name="submit" value="Submit" /></div>
</form>
【问题讨论】:
代码?错误?什么? 书上不代表对,请分享代码。 你放弃了这个帖子@user3286022 吗? 【参考方案1】:您需要在文件路径中包含文件扩展名。一种方法是:
$path_parts = pathinfo($_FILES["file"]["name"]);
$extension = $path_parts['extension'];
然后您只需要更改这行代码:
rename ($temp, "../../uploads/$id");
到:
rename ($temp, "../../uploads/$id.".".$extension");
如果您计划接受多种图像格式,那么将其文件扩展名连同它一起存储在数据库中总是值得的。这样,只需要一个简短的函数来生成文件名,同时仍然保持整数 id 用于搜索/链接到其他数据库的灵活性
【讨论】:
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