wustoj 1593: Count Zeros线段树

Posted 2022-12-10 mfcheer

题目：http://acm.wust.edu.cn/problem.php?id=1593&soj=0

解法：线段树维护因子2 5存在的个数。并判断是不是存在0

代码：

#include <stdio.h>
#include <iostream>
#include <string>
#include <cstring>
#include <cmath>
#include <cstdlib>
#include <algorithm>
#include <queue>
#include <stack>
#include <set>
#include <map>
#include <vector>

const int N = 200010;

using namespace std;

int m, n;
int a[N];

struct node

    int left;
    int right;
    int sum2, sum5;
    bool is;
;

struct segtree

    node tree[N * 4];

    void buildtree(int left, int right, int ind)
    
        tree[ind].left = left;
        tree[ind].right = right;
        tree[ind].sum2 = tree[ind].sum5 = 0;
        tree[ind].is = false;

        if (left == right)
        
            if (a[left] == 0)
            
                tree[ind].is = true;
                return;
            

            int tmp1 = a[left];
            while (tmp1 != 0 && tmp1 % 2 == 0)
            
                tree[ind].sum2++;
                tmp1 /= 2;
            

            tmp1 = a[left];
            while (tmp1 != 0 && tmp1 % 5 == 0)
            
                tree[ind].sum5++;
                tmp1 /= 5;
            
        
        else
        
            int mid = (tree[ind].left + tree[ind].right) / 2;

            buildtree(left, mid, 2*(ind));
            buildtree(mid + 1, right,2*(ind) + 1);

            tree[ind].sum2 = (tree[2*(ind)].sum2 + tree[2*(ind) + 1].sum2);
            tree[ind].sum5 = (tree[2*(ind)].sum5 + tree[2*(ind) + 1].sum5);
            tree[ind].is = (tree[2*(ind)].is || tree[2*(ind) + 1].is);
        
    

    void update(int pos, int ind, int val)
    
        if (tree[ind].left == tree[ind].right)
        
            if (val == 0)
                tree[ind].is = true;
            else
                tree[ind].is = false;

            int tmp1;
            tree[ind].sum2 = 0;
            tmp1 = val;
            while (tmp1 != 0 && tmp1 % 2 == 0)
            
                tree[ind].sum2++;
                tmp1 /= 2;
            

            tree[ind].sum5 = 0;
            tmp1 = val;
            while (tmp1 != 0 && tmp1 % 5 == 0)
            
                tree[ind].sum5++;
                tmp1 /= 5;
            
        
        else
        
            int mid = (tree[ind].left + tree[ind].right)/2;
            if (pos <= mid)
                update(pos, 2*(ind), val);
            else
                update(pos, 2*(ind) + 1, val);
            tree[ind].sum2 = (tree[2*(ind)].sum2 + tree[2*(ind)+1].sum2);
            tree[ind].sum5 = (tree[2*(ind)].sum5 + tree[2*(ind) + 1].sum5);
            tree[ind].is = (tree[2*(ind)].is || tree[2*(ind) + 1].is);
        
    

    int query2(int st, int ed, int ind)
    
        int left = tree[ind].left;
        int right = tree[ind].right;

        if (st <= left && right <= ed)
        
            return tree[ind].sum2;
        
        else
        
            int mid = (tree[ind].left + tree[ind].right) / 2;
            int sum1 = 0;
            int sum2 = 0;
            if (st <= mid)
                sum1 = query2(st, ed, 2*(ind));
            if (ed > mid)
                sum2 = query2(st, ed, 2*(ind) + 1);
            return (sum1 + sum2);
        
    
    int query5(int st, int ed, int ind)
    
        int left = tree[ind].left;
        int right = tree[ind].right;

        if (st <= left && right <= ed)
            return tree[ind].sum5;
        else
        
            int mid = (tree[ind].left + tree[ind].right) / 2;
            int sum1 = 0;
            int sum2 = 0;
            if (st <= mid)
                sum1 = query5(st, ed, 2*(ind));
            if (ed > mid)
                sum2 = query5(st, ed, 2*(ind) + 1);
            return (sum1 + sum2);
        
    
    bool query0(int st, int ed, int ind)
    
        int left = tree[ind].left;
        int right = tree[ind].right;

        if (st <= left && right <= ed)
        
            if (tree[ind].is == false)
                return false;
            else
                return true;
        
        else
        
            int mid = (tree[ind].left + tree[ind].right) / 2;
            int sum1 = 0;
            int sum2 = 0;
            if (st <= mid)
                sum1 = query0(st, ed, 2*(ind));
            if (ed > mid)
                sum2 = query0(st, ed, 2*(ind) + 1);
            return (sum1 || sum2);
        
    
seg;

int main()

    while (scanf("%d %d", &n, &m) != EOF)
    
        for (int i = 1; i <= n; i++)
            scanf("%d", &a[i]);

        seg.buildtree(1, n, 1);

        int opr, c, d;
        while (m--)
        
            scanf("%d", &opr);
            scanf("%d %d", &c, &d);
            if (opr == 0)
            
                int s2, s5;
                bool s0 = seg.query0(c, d, 1);
                s2 = seg.query2(c, d, 1);
                s5 = seg.query5(c, d, 1);

                int ans = min(s2, s5);
                if (s0)
                    ans = 1;
                printf("%d\\n", ans);
            
            else if (opr == 1)
            
                seg.update(c, 1, d);
            
        
    
    return 0;