集体拍照

Posted 2022-11-21 爱coding的卖油翁

集体拍照排序

今天一朋友面试，遇到一个算法题，我正好看到了，就来解一下，不是最优解，先记录一下吧。

要求如下：

• 每排人数为N/K（向下取整），多出来的人数全部站在最后一排
• 后排所有人的个子都不比前排任何人矮
• 每排中最高者站中间（中间位置为m/2+1，其中m为该排人数，除法向下取整）
• 每排其他人以中间人为轴，按身高非增序，先右后左交替入队站在中间人的两侧（例如5人身高为190、188、186、175、170，则队形为175、188、190、186、170。这里加入你面对拍照者，所以你的左边是中间人的右边）
• 若多人身高相同，则按名字的字典升序排序。这里保证无重名
• 现在给定一组拍照人，请编写出他们的队形

输入格式：

• N：总人数（<=10000） K：总排数（<=10）

输出格式：

• 输出拍照的队形。
• 即K排人名，其间以空格分隔，行末不得有多余空格。
• 注意：假设你面对拍照者，后排的人输出在上方，前排输出在下方。

输入

10 3
Tom 188 Mike 170 Eva 168 Tim 160 Joe 190 Ann 168 Bob 175 Nick 186 Amy 160 John 159

输出

Bob Tom Joe Nick
Ann Mike Eva
Tim Amy John

代码如下：

public class TakeCamera 

    public static void main(String[] args) 

        List<People> list = new ArrayList<>();
        People people = new People("Tom", 188);
        list.add(people);
        people = new People("Mike", 170);
        list.add(people);
        people = new People("Eva", 168);
        list.add(people);
        people = new People("Tim", 160);
        list.add(people);
        people = new People("Joe", 190);
        list.add(people);
        people = new People("Ann", 168);
        list.add(people);
        people = new People("Bob", 175);
        list.add(people);
        people = new People("Nick", 186);
        list.add(people);
        people = new People("Amy", 160);
        list.add(people);
        people = new People("John", 159);
        list.add(people);

        new TakeCameraSort().sort(3, list);
    


class TakeCameraSort 

    public void sort(int column, List<People> list) 
        int size = list.size();
        for (int i = 0; i < column; i++) 

            // 计算最后一行的人数
            int temp;
            if (i == 0) 
                temp = size / column + size % column;
             else 
                temp = size / column;
            

            // 初始化每一行的人数
            List<People> tempList = new ArrayList<>();
            for (int j = 0; j < temp; j++) 
                People people = list.get(j);
                people.temp = j;
                tempList.add(people);
            

            // 获取最小值
            People min = min(tempList);

            for (int j = temp; j < list.size(); j++) 
                People people = list.get(j);
                if (people.height > min.height) 
                    // 更换list中的最小值
                    people.temp = min.temp;
                    tempList.remove(min.temp);
                    tempList.add(people.temp, people);

                    // // 获取最小值
                    min = min(tempList);
                
            

            // 对每一行进行排序
            People[] peoples = rowSort(tempList);

            // 打印
            for (int j = 0; j < peoples.length; j++) 
                People p = peoples[j];
                // 去除最后一行的空格
                if (j == peoples.length - 1) 
                    System.out.print(p.name);
                 else 
                    System.out.print(p.name + " ");
                
                list.remove(p);
            
            System.out.println();
        
    

    /**
     * 对每一行进行排序
     */
    private People[] rowSort(List<People> list) 
        int size = list.size();
        int left = 1;
        int right = 1;
        int max = size / 2;
        People[] temp = new People[size];
        for (int i = 0; i < size; i++) 
            People people = max(list);
            if (i == 0) 
                temp[max] = people;
             else if (i % 2 == 0) 
                temp[max + right] = people;
                right++;
             else 
                temp[max - left] = people;
                left++;
            
            list.remove(people);
        
        return temp;
    

    /**
     * 获取最大值
     */
    private People max(List<People> peoples) 
        People max = peoples.get(0);
        for (People p : peoples) 
            if (max.height < p.height) 
                max = p;
             else if (max.height == p.height) 
                int compare = max.name.compareTo(p.name);
                if (compare > 0)
                    max = p;
            
        
        return max;
    

    /**
     * 获取最小值
     */
    private People min(List<People> peoples) 
        People min = peoples.get(0);
        for (People p : peoples) 
            if (min.height > p.height) 
                min = p;
             else if (min.height == p.height) 
                int compare = min.name.compareTo(p.name);
                if (compare > 0)
                    min = p;
            
        
        return min;
    



class People 

    String name;
    int height;
    int temp;   // 临时位置

    public People(String name, int height) 
        this.name = name;
        this.height = height;