Leetcode 42 接雨水

Posted 2022-10-27 alf_cee

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动态规划方法：

class Solution 
    public int trap(int[] height) 
        int length = height.length;
        int[] leftLength = new int[length];
        int[] rigthLength = new int[length];
        int lefhMax = 0;
        int rigthMax = 0;
        //从左往右获取最高点
        for (int i = 0; i < height.length; i++) 
            lefhMax = Math.max(height[i], lefhMax);
            if (i == 0)
                leftLength[i] = 0;
             else 
                int left = lefhMax - height[i];
                if (left <=0 )
                    leftLength[i] = 0;
                 else 
                    leftLength[i] = left;
                
            
        

        for (int i = height.length - 1; i >= 0; i--) 
            rigthMax = Math.max(height[i], rigthMax);
            if(i == height.length - 1)
                rigthLength[i] = 0;
             else 
                int right = rigthMax - height[i];
                if (right <= 0)
                    rigthLength[i] = 0;
                 else 
                    rigthLength[i] = right;
                
            
        

        int vol = 0;
        for (int i = 0; i < height.length; i++) 
            int iVol = Math.min(leftLength[i], rigthLength[i]);
            if (iVol > 0)
//                System.out.println("i=" + i + ", iVol=" + iVol);
                vol += iVol;
             else 
//                System.out.println("i=" + i + ", iVol=" + 0);
            

        
//        System.out.println("vol =" + vol);
        return vol;

参考：leetcode 42. 接雨水（双指针、动态规划、单调栈）_The August的博客-CSDN博客

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