List.contains(Object object)方法
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使用List.contains(Object object)方法判断ArrayList是否包含一个元素对象(针对于对象的属性值相同,但对象地址不同的情况),如果没有重写List<E>的元素对象Object中的equals方法,默认如下:
@Override
public boolean equals(Object o)
// TODO Auto-generated method stub
return super.equals(o);
将导致contains方法始终返回false。
查看ArrayList的contains方法的源码如下:
/**
* Searches this @code ArrayList for the specified object.
*
* @param object
* the object to search for.
* @return @code true if @code object is an element of this
* @code ArrayList, @code false otherwise
*/
@Override public boolean contains(Object object)
Object[] a = array;
int s = size;
if (object != null)
for (int i = 0; i < s; i++)
if (object.equals(a[i]))
return true;
else
for (int i = 0; i < s; i++)
if (a[i] == null)
return true;
return false;
可以看出,contains方法依据Object的equals方法来判断是否包含某一元素,继续查看Object类中的equals方法,源码如下:
public boolean equals(Object o)
return this == o;
所以,使用“==”比较对象的地址,如果是同一对象即地址相同的情况下,才会返回true,而对于对象属性值相同但地址不同的不同对象,始终返回false!
如果需要依据对象属性值是否相同来判断ArrayList是否包含某一对象,则需要重写Object的equals方法,并在equals方法中一一比较对象的每个属性值,如:
package com.feng.lejuan.entity;
public class QuestionInfo
private String questionId;
private String answerId;
private String subQuestionId;
private String result;
public QuestionInfo()
super();
public QuestionInfo(String questionId, String answerId,
String subQuestionId, String result)
super();
this.questionId = questionId;
this.answerId = answerId;
this.subQuestionId = subQuestionId;
this.result = result;
public String getQuestionId()
return questionId;
public void setQuestionId(String questionId)
this.questionId = questionId;
public String getAnswerId()
return answerId;
public void setAnswerId(String answerId)
this.answerId = answerId;
public String getSubQuestionId()
return subQuestionId;
public void setSubQuestionId(String subQuestionId)
this.subQuestionId = subQuestionId;
public String getResult()
return result;
public void setResult(String result)
this.result = result;
@Override
public boolean equals(Object o)
if (o instanceof QuestionInfo)
QuestionInfo question = (QuestionInfo) o;
return this.questionId.equals(question.questionId)
&& this.subQuestionId.equals(question.subQuestionId)
&& this.answerId.equals(question.answerId)
&& this.result.equals(question.result);
return super.equals(o);
@Override
public String toString()
return "QuestionInfo [questionId=" + questionId + ", answerId="
+ answerId + ", subQuestionId=" + subQuestionId + ", result="
+ result + "]";
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List.contains(Object object)方法