LeetCode（剑指 Offer）- 12. 矩阵中的路径

Posted 2022-04-23 放羊的牧码

题目链接：点击打开链接

题目大意：略

解题思路：略

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AC 代码

• Java

// 解决方案(1)
class Solution 

    // 使用 Map 超时
//    private Map<Integer, Boolean> usedMap = new HashMap<>();

    private boolean ok = false;

    private boolean[][] path;

    public boolean exist(char[][] board, String word) 
        path = new boolean[board.length][board[0].length];
        for (int i = 0; i < board.length; i++) 
            for (int j = 0; j < board[i].length; j++) 
                if (ok) 
                    return true;
                
//                usedMap.clear();
                // 不需要每次都初始化, 比较耗时, 因为回溯的时候会恢复到原始状态
//                path = new boolean[board.length][board[0].length];
                handle(board, i, j, word, 0);
            
        
        return ok;
    

    private void handle(char[][] board, int i, int j, String word, int ptr) 
        if (ok || i >= board.length || i < 0 || j >= board[0].length || j < 0) 
            return;
        

//        Integer key = i * 10 + j;
        if (path[i][j]) 
            return;
        

        if (board[i][j] == word.charAt(ptr)) 
            if (ptr + 1 >= word.length()) 
                ok = true;
                return;
            
            path[i][j] = true;
//            usedMap.put(key, true);
            handle(board, i + 1, j, word, ptr + 1);
            handle(board, i - 1, j, word, ptr + 1);
            handle(board, i, j + 1, word, ptr + 1);
            handle(board, i, j - 1, word, ptr + 1);
//            usedMap.remove(key);
            path[i][j] = false;
        
    


// 解决方案(2)
class Solution 
    public boolean exist(char[][] board, String word) 
        char[] words = word.toCharArray();
        for(int i = 0; i < board.length; i++) 
            for(int j = 0; j < board[0].length; j++) 
                if(dfs(board, words, i, j, 0)) return true;
            
        
        return false;
    
    boolean dfs(char[][] board, char[] word, int i, int j, int k) 
        if(i >= board.length || i < 0 || j >= board[0].length || j < 0 || board[i][j] != word[k]) return false;
        if(k == word.length - 1) return true;
        board[i][j] = '\\0';
        boolean res = dfs(board, word, i + 1, j, k + 1) || dfs(board, word, i - 1, j, k + 1) || 
                      dfs(board, word, i, j + 1, k + 1) || dfs(board, word, i , j - 1, k + 1);
        board[i][j] = word[k];
        return res;
    

• C++

class Solution 
public:
    bool exist(vector<vector<char>>& board, string word) 
        rows = board.size();
        cols = board[0].size();
        for(int i = 0; i < rows; i++) 
            for(int j = 0; j < cols; j++) 
                if(dfs(board, word, i, j, 0)) return true;
            
        
        return false;
    
private:
    int rows, cols;
    bool dfs(vector<vector<char>>& board, string word, int i, int j, int k) 
        if(i >= rows || i < 0 || j >= cols || j < 0 || board[i][j] != word[k]) return false;
        if(k == word.size() - 1) return true;
        board[i][j] = '\\0';
        bool res = dfs(board, word, i + 1, j, k + 1) || dfs(board, word, i - 1, j, k + 1) || 
                      dfs(board, word, i, j + 1, k + 1) || dfs(board, word, i , j - 1, k + 1);
        board[i][j] = word[k];
        return res;
    
;