273. Integer to English Words
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Convert a non-negative integer to its english words representation. Given input is guaranteed to be less than 231 - 1.
Example 1:
Input: 123 Output: "One Hundred Twenty Three"
Example 2:
Input: 12345 Output: "Twelve Thousand Three Hundred Forty Five"
Example 3:
Input: 1234567 Output: "One Million Two Hundred Thirty Four Thousand Five Hundred Sixty Seven"
Example 4:
Input: 1234567891 Output: "One Billion Two Hundred Thirty Four Million Five Hundred Sixty Seven Thousand Eight Hundred Ninety One"
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????????????????????????0-1 billion?????????
????????????????????????1??????0??????0??????0??????0??????0??????0??????0??????0??????0
?????????????????????billion????????????????????? million??????????????????thousand hundred?????????
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????????????????????????unit ???hash map????????????????????????0?????????????????????????????????
??????1-9??? 10-19??? 20??? 30??? 40??? 50??? 60??? 70 ???80??? 90????????????
???num?????????1000?????????????????????3????????????????????????????????????????????????????????????count?????????????????????
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class Solution { public: string numberToWords(int num) { unordered_map<int,string> dict ={ {1, "One"}, {2, "Two"}, {3, "Three"}, {4, "Four"}, {5, "Five"}, {6, "Six"}, {7, "Seven"}, {8, "Eight"}, {9, "Nine"}, {10, "Ten"},{11, "Eleven"}, {12, "Twelve"}, {13, "Thirteen"}, {14, "Fourteen"}, {15, "Fifteen"},{16, "Sixteen"}, {17, "Seventeen"}, {18, "Eighteen"}, {19, "Nineteen"}, {20, "Twenty"}, {30, "Thirty"}, {40, "Forty"}, {50, "Fifty"}, {60, "Sixty"}, {70, "Seventy"}, {80, "Eighty"}, {90, "Ninety"} }; unordered_map<int,string> unit = {{0, ""},{1, " Thousand"}, {2, " Million"}, {3," Billion"}}; string ret = ""; int count = 0; if(num == 0) return "Zero"; while(num > 0){ int cur = num % 1000; if(cur != 0){ string wn = toWords(cur, dict); wn += unit[count]; if(ret.size() != 0){ ret = " "+ret; } ret = wn + ret; } count++; num /= 1000; } return ret; } private: string toWords(int n, unordered_map<int, string> &m){ string ret; int h = n/100; if(h != 0) ret = m[h] + " Hundred"; n %= 100; if(n == 0) return ret; if(m.count(n)){ if(ret.size() != 0) ret += " "; ret += m[n]; }else{ int t = n/10; if(t != 0){ if(ret.size() != 0) ret += " "; ret += m[t*10]; } int d = n%10; if(d != 0){ if(ret.size() != 0) ret += " "; ret += m[d]; } } return ret; } };
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[LC] 273. Integer to English Words