缺少类型说明符 - 假定为 int。注意: C++ 不支持默认 int----;解决方法

Posted 2022-03-11 Potter

写了一个对应让其出的错误（其实也挺不容易的喔 ）

错误如下：

1>d:\\work\\win32project\\testeachotherclude\\testeachotherclude\\test2.h(9): error C2143: 语法错误 : 缺少“;”(在“*”的前面)
1>d:\\work\\win32project\\testeachotherclude\\testeachotherclude\\test2.h(9): error C4430: 缺少类型说明符 - 假定为 int。注意: C++ 不支持默认 int
1>d:\\work\\win32project\\testeachotherclude\\testeachotherclude\\test2.h(9): error C4430: 缺少类型说明符 - 假定为 int。注意: C++ 不支持默认 int
1>d:\\work\\win32project\\testeachotherclude\\testeachotherclude\\test2.h(10): error C2061: 语法错误: 标识符“Test1”
1>d:\\work\\win32project\\testeachotherclude\\testeachotherclude\\testeachotherclude.cpp(15): error C2660: “Test2::className”: 函数不接受 1 个参数
1>d:\\work\\win32project\\testeachotherclude\\testeachotherclude\\testeachotherclude.cpp(16): error C2039: “test1”: 不是“Test2”的成员
1>          d:\\work\\win32project\\testeachotherclude\\testeachotherclude\\test2.h(7) : 参见“Test2”的声明
1>d:\\work\\win32project\\testeachotherclude\\testeachotherclude\\testeachotherclude.cpp(16): error C2227: “->refMe”的左边必须指向类/结构/联合/泛型类型

上传Test方便大家看：

main.cpp

#include "stdafx.h"
#include "Test1.h"
#include "Test2.h"

int _tmain(int argc, _TCHAR* argv[])

	Test1* t1=new Test1();
	Test2* t2=new Test2();
	t1->className(t2);
	t1->test2->refMe();

	t2->className(t1);
	t2->test1->refMe();
	return 0;

再来看Test1的

Test1.h

#ifndef Test1_H
#define Test1_H

#include "Test2.h"

class Test1

public:
	Test2* test2;
	void Test1::className(Test2* test2);
	void refMe();
;
#endif;

Test1.cpp

#include "Test2.h"

void Test1::className(Test2* test2)

	this->test2=test2;
	std::cout<<"Test1  ";


void Test1::refMe()

	std::cout<<"refMe Test1"<<std::endl;

Test2.h

#ifndef Test2_H
#define Test2_H

#include "Test1.h"

class Test2

public:
	Test1* test1;
	void className(Test1* test1);
	void refMe();
;
#endif

Test2.cpp

#include "StdAfx.h"
#include "Test2.h"
#include <iostream>

void Test2::className(Test1* test1)

	this->test1=test1;
	std::cout<<"Test2  ";


void Test2::refMe()

	std::cout<<"refMe Test2"<<std::endl;

然后运行就报上面的一对错误了...

仔细看看发现两个头文件都彼此包含了，就是这个问题啦...那我们怎么解决了，上传我的代码，直接看这样更容易理解  main.cpp不变

Test1.h

#ifndef Test1_H
#define Test1_H
//#include "Test2.h" //用下面的方式替代
class Test2;//注意：只是告诉编译器,需要这个类,其他功能结构等都没

class Test1

public:
	Test2* test2;
	void Test1::className(Test2* test2);
	void refMe();
;
#endif;

 Test1.cpp

#include "StdAfx.h"
#include "Test1.h"
#include <iostream>

#include "Test2.h" //注意：这里才是真正的包含

void Test1::className(Test2* test2)

	this->test2=test2;
	std::cout<<"Test1  ";


void Test1::refMe()

	std::cout<<"refMe Test1"<<std::endl;

Tes2的我就不贴了，一样的道理，编译运行ok ....