array_merge（）：参数2不是旁过滤器上的数组

Posted 2021-05-07

我在一个问题上遇到麻烦了。在侧边栏筛选器功能中，当我单击复选框时，它将正确显示list。但是，当我取消选中复选框时，它将显示“ array_merge（）：参数＃2不是数组”，当检查元素时显示此错误。当我单击复选框时，它将生成此URL“ http://abc.local/genre-tags/?id%5B%5D=31”。当我取消选中复选框时，它将显示错误的URL“ http://abc.local/genre-tags/”。以下是控制器和js代码。

//控制器

public function genresFilter ()
    {
        $sortBy = Input::get('sortBy', 'id');
        $dir    = Input::get('direction', 'desc');

        $orderBy = [
                        'tracks'=>[   'order_by'=>$sortBy, 'direction'=>$dir ]
                    ];

        $id = Input::get('id');

        $category = Category::where('slug','music-genre')->first();

        $tag = Tag::with('tracks','elements')->where('category_id', $category->id)->whereIn('id', $id)->get();
        echo "<pre>";
        print_r($tag->toArray());
        die();

        $this->layout->content = View::make('public.tags.genres', compact('tag'));
    }

// js

//Sidebar Filter Genre Tracks
$(document).ready(function () {
    $('.genreTag').on('change', function (e)
    {

        $('input.filter-playlist, .popularGenreTag, .mood-emotion, .production-type, .vocals, .all-tracks, .last-year, .last-month, .last-week, .last-day').each(function() {
            var $this = $(this);
            $this.prop('checked', false);
            $this.parent().find('> div').removeClass('chk-checked').addClass('chk-unchecked');
        });

        e.preventDefault();
        id = [];

        $('.genreTag:checked').each(function()
        {
            id.push($(this).attr('id'));
        });

        $.get("/genre-tags/", {id: id}, function(data)
        {
            hideLoader();
            refreshedPage = $(data);
            newDemo = refreshedPage.find(".libraryWrapper, .albumWrapper, .composersWrapper, .albumsListWrapper, .albumsWrapper, .accountWrapper, .distributionsWrapper, .PaymentsWrapper, .contactWrapper, .contractsWrapper, .toolsWrapper, .blogWrapper, .pageWrapper, .cartWrapper, .pageWrapper").html();

            $('.libraryWrapper, .albumsWrapper, .albumWrapper, .composersWrapper, .albumsListWrapper, .accountWrapper, .distributionsWrapper, .PaymentsWrapper, .contactWrapper, .contractsWrapper, .toolsWrapper, .blogWrapper, .pageWrapper, .cartWrapper, .pageWrapper').html(newDemo);
            activatePlayer()
            initTrackInfo();
        });
    });
});


//route
Route::get('genre-tags/', ['as' => 'tag.popular-genres', 'uses' => 'SideFilterController@genresFilter']);

//checkbox blade file

<li class="lib">
            <label><input class="genreTag"  id="{{ $genreTag->id}}" type="checkbox" name="" value="{{ $genreTag->name }}">{{{ $genreTag->name }}} ({{count(json_decode($genreTag->elements, true))+ count(json_decode($genreTag->tracks, true))}}) </label>
        </li>

答案

我认为您的控制器存在问题：您有whereIn查询，需要在第二个参数上传递数组。但是您的ID为null，因此为什么会出现此类错误。尝试将代码更改为下面的代码将起作用。

public function genresFilter ()
    {
        $sortBy = Input::get('sortBy', 'id');
        $dir    = Input::get('direction', 'desc');

        $orderBy = [
                        'tracks'=>[   'order_by'=>$sortBy, 'direction'=>$dir ]
                    ];

        $id = Input::get('id');

        // check if id is not array, then give empty array
        if(!is_array($id)) $id = [];

        $category = Category::where('slug','music-genre')->first();

        $tag = Tag::with('tracks','elements')->where('category_id', $category->id)->whereIn('id', $id)->get();
        echo "<pre>";
        print_r($tag->toArray());
        die();

        $this->layout->content = View::make('public.tags.genres', compact('tag'));
    }