错误：没有用于调用'variable'的匹配函数

Posted 2021-05-06

我正在学习c ++，我已经初始化了一个变量（chars向量的向量），然后添加了一个函数原型，然后在main中调用了该函数。

但我看到error: no matching function for call to 'std::vector<std::vector<char> >::vector(<brace-enclosed initializer list>)'

我认为错误信息是：

“嘿，你试图调用函数'std::vector<std::vector<char> >::vector(<brace-enclosed initializer list>)'，但它不存在。”

但据我所知，我从未尝试将其称为函数，我只是尝试将其初始化为变量。

#include <iostream>
#include <vector>

int main()
{
    std::vector<std::vector<char>> board {{"5","3",".",".","7",".",".",".","."},{"6",".",".","1","9","5",".",".","."},{".","9","8",".",".",".",".","6","."},{"8",".",".",".","6",".",".",".","3"},{"4",".",".","8",".","3",".",".","1"},{"7",".",".",".","2",".",".",".","6"},{".","6",".",".",".",".","2","8","."},{".",".",".","4","1","9",".",".","5"},{".",".",".",".","8",".",".","7","9"}};
    return 0;
}

答案

定义std::vector的对象时，将选择适当的构造函数来初始化对象。编译器只是抱怨无法找到合适的构造函数。请注意，构造函数也是一个函数。

这里的问题是内部vector的元素类型是char，但"5"和"3"等是c风格的字符串，即const char[2]s，而不是chars。

将所有"更改为'。

std::vector<std::vector<char>> board {{'5','3','.','.','7','.','.','.','.'},{'6','.','.','1','9','5','.','.','.'},{'.','9','8','.','.','.','.','6','.'},{'8','.','.','.','6','.','.','.','3'},{'4','.','.','8','.','3','.','.','1'},{'7','.','.','.','2','.','.','.','6'},{'.','6','.','.','.','.','2','8','.'},{'.','.','.','4','1','9','.','.','5'},{'.','.','.','.','8','.','.','7','9'}};