防止在随机播放模式下重复播放
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如何在测验中随机抽出我已经问过的问题(这样就不重复了)?在不破坏应用程序的情况下实现此目标的最佳方法是什么?
问题:我想只保留一个带有所有问题的Java类,不知道在进行其他Level活动时这是否是一个好方法。所以我开始尝试10个问题,但我一直在问问题。然后我把这个类分成两个(每个5个问题),用新级别定义每个级别(Easy Level 1和2),但问题是相同的。
我想,这就是我在逻辑部分挣扎的路线:
updateQuestion(rand.nextInt(mQuestionsLength));
这是我试过的,直到现在:
public class Quiz extends AppCompatActivity {
Button answer1, answer2;
TextView score, question, timer;
private Question mQuestions = new Question();
private String mExplanation;
private String mAnswer;
private int mScore = 0;
private int mQuestionNumber = 0;
private String mQuestionsIndex;
private int mAns = 0;
public int mQuestionsLength = mQuestions.mQuestions.length;
Random rand;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_easy_level1);
rand = new Random();
answer1 = (Button)findViewById(R.id.answer1);
answer2 = (Button)findViewById(R.id.answer2);
score = (TextView) findViewById(R.id.score);
question = (TextView) findViewById(R.id.question);
timer = (TextView) findViewById(R.id.timer);
score.setText("Overall Score: " + mScore);
updateQuestion(rand.nextInt(mQuestionsLength));
answer1.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
if(answer1.getText() == mAnswer){
bingoAlert();
} else {
oopsAlert();
}
}
});
answer2.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
if(answer2.getText() == mAnswer){
bingoAlert();
} else {
oopsAlert();
}
}
});
}
private void updateQuestion(int num){
question.setText(mQuestions.getQuestion(num));
answer1.setText(mQuestions.getChoice1(num));
answer2.setText(mQuestions.getChoice2(num));
mAnswer = mQuestions.getCorrectAnswer(num);
mQuestionsIndex = mQuestions.getQuestionIndex(num);
mQuestionNumber++;
}
private void bingoAlert(){
mScore+=5;
score.setText("Score: " + mScore);
if(mQuestionNumber == mQuestions.mQuestions.length){
// Do something...
}else{
updateQuestion(rand.nextInt(mQuestionsLength));
}
}
private void oopsAlert(){
mScore-=2;
score.setText("Score: " + mScore);
if(mQuestionNumber == mQuestions.mQuestions.length){
// Do something...
}else{
updateQuestion(rand.nextInt(mQuestionsLength));
}
}
问题类
public class Questions {
public static String[] mQuestions = new String[]{
"Question 1",
"Question 2",
"Question 3",
"Question 4",
"Question 5"
};
public static String[] mQuestionsIndex = new String[]{
"1", "2", "3", "4", "5"
};
private static String mChoices[][] = {
{"Choice 1", "Choice 2"},
{"Choice 1", "Choice 2"},
{"Choice 1", "Choice 2"},
{"Choice 1", "Choice 2"},
{"Choice 1", "Choice 2"}
};
private String mCorrectAnswers[] =
{"Choice 1", "Choice 2", "Choice 1", "Choice 2", "Choice 1"};
public String getQuestion(int a) {
String question = mQuestions[a];
return question;
}
public String getChoice1(int a) {
String choice = mChoices[a][0];
return choice;
}
public String getChoice2(int a) {
String choice = mChoices[a][1];
return choice;
}
public String getCorrectAnswer(int a) {
String answer = mCorrectAnswers[a];
return answer;
}
public String getQuestionIndex(int a) {
String questionsIndex = mQuestionsIndex[a];
return questionsIndex;
}
这是我的随机类
class RandomClass {
private Random randNum;
public RandomClass() {
randNum = new Random();
}
public int[] generateRandomArray(int arraySize){
int[] theArray = new int[arraySize];
for(int mQuestionNumber = 0; mQuestionNumber <= 5; mQuestionNumber++){
theArray[mQuestionNumber] = randNum.nextInt(6);
}
return theArray;
}
}
这是我最近的尝试:
private void updateQuestion(int num){
question.setText(mQuestions.getQuestion(num));
answer1.setText(mQuestions.getChoice1(num));
answer2.setText(mQuestions.getChoice2(num));
mAnswer = mQuestions.getCorrectAnswer(num);
mExplanation = mQuestions.getExplanation(num);
mQuestionsIndex = mQuestions.getQuestionIndex(num);
for (int mQuestionNumber = 0; mQuestionNumber <= 5; mQuestionNumber++) {
int[] ints = new RandomClass().generateRandomArray(5);
}
}
谢谢!
答案
提示:保持一个ArrayList
- 创建一个ArrayList。
- 添加问题的索引。例如:1,2,3,4 ..... n在列表中。
- 生成List大小范围内的随机数。
- 显示与生成的随机数对应的问题(最好是问题编号的索引)。
- 显示问题后,从列表中删除该项目。
- 当您从列表中删除项目时,列表会更新,并且已删除元素之后的所有元素都会向上移动一个位置,并且列表的大小会更新(减少1)。
- 再次生成列表大小范围内的随机数并重复该过程。
list.get(random_number);
将为您提供存储在该位置的数字的索引,以便您可以相应地显示您的位置。
如果有任何意见不明确或含糊不清,请告诉我。我会更新它。
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