更改脚本以在特定工作表上运行会引发TypeError

Posted 2021-05-06

如何在特定工作表而不是整个电子表格上运行此脚本？

function deleteQCOrder() {
  var sheet = SpreadsheetApp.getActiveSheet();
  var rows = sheet.getDataRange();
  var numRows = rows.getNumRows();
  var values = rows.getValues();

  var rowsDeleted = 0;
  for (var i = 0; i <= numRows - 1; i++) {
    var row = values[i];
    if (row[4] == 'Delete' || row[4] == '') { // This searches all cells in columns A (change to row[1] for columns B and so on) and deletes row if cell is empty or has value 'delete'.
      sheet.deleteRow((parseInt(i)+1) - rowsDeleted);
      rowsDeleted++;
    }
  }
};

例如，如果我想在“Sheet1”上运行它，我试过：

function deleteQCOrder() {
  var sheet = SpreadsheetApp.getActiveSheet();

  var ss = sheet.getSheetByName('Sheet1');

  var rows = ss.getDataRange();
  var numRows = rows.getNumRows();
  var values = rows.getValues();

  var rowsDeleted = 0;
  for (var i = 0; i <= numRows - 1; i++) {
    var row = values[i];
    if (row[4] == 'Delete' || row[4] == '') { // This searches all cells in columns A (change to row[1] for columns B and so on) and deletes row if cell is empty or has value 'delete'.
      sheet.deleteRow((parseInt(i)+1) - rowsDeleted);
      rowsDeleted++;
    }
  }
};

但是没有运行，我得到这个错误：

TypeError：在对象Sheet中找不到函数getSheetByName。 （第3行，文件“删除订单号”）

答案

您在代码中执行的操作是获取sheet对象，该对象当前是活动工作表

var sheet = SpreadsheetApp.getActiveSheet();

那么你试图从一个工作表对象中获取一个工作表对象，这就是错误

var ss = sheet.getSheetByName('Sheet1');

您需要做的是从电子表格对象中找到一个工作表对象，如下所示：

function deleteQCOrder() {
  //correct use of SpreadsheetApp for your case
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getSheetByName('Sheet1');
  var range = sheet.getDataRange();
  var numRows = range.getNumRows();
  var values = range.getValues();
  var rowsDeleted = 0;
  for (var i = 0; i <= numRows - 1; i++) {
    var row = values[i];
    if (row[4] == 'Delete' || row[4] == '') {
      sheet.deleteRow((parseInt(i)+1) - rowsDeleted);
      rowsDeleted++;
    }
  }
};

另一答案

您必须使用电子表格对象来获取工作表对象。在第二个代码块中，您将获得工作表而不是电子表格。

您可以使用以下方式获取电子表格对象：

var ss = SpreadsheetApp.getActiveSpreadsheet();

然后你可以使用getSheetByName获取'Sheet1'：

var sheet = ss.getSheetByName('Sheet1');