MDX Crossjoin地区和国家和总计

Posted 2021-05-05

我需要加入两个层次结构，Region和Country。从我们的立方体我必须得到一个由1个地区和2个国家组成的结果。这就是我到目前为止所做的：

SET [RegionSet] AS 
  {
     [Stores].[Region].&[EUROPE]
  }

SET [CountrySet] AS 
  {
     [Stores].[Country].&[Japan]&[APAC]
    ,[Stores].[Country].&[China]&[APAC]
  }


NON EMPTY
  (
   {
    [RegionSet]
  , [Stores].[Region].[All]
   }
  ) 
* (
   {
    [CountrySet]
  , [Stores].[Country].[All]
   }
  )
    ON ROWS

MSD结果如下：

但我想在没有All条目的情况下列出一列中的区域和国家，并在最后一行添加总计。我怎样才能做到这一点？

答案

我想如果你有一个名为[Geography]的多级用户层次结构作为[Stores]维度的一部分，那么我认为这将是微不足道的：

SET [RegionCountrySet] AS 
  {
     [Stores].[Geography].[Region].&[EUROPE]
    ,[Stores].[Geography].[Country].&[Japan]&[APAC]
    ,[Stores].[Geography].[Country].&[China]&[APAC]
  }

...但您可以创建自定义聚合成员。然后在行上使用创建的成员：

1. 选择一个未使用的层次结构来“托管”你的新成员。我假设你有一个[Languages]维度。新成员将作为子项添加到所选层次结构的[All]成员中。
2. 从目标创建元组，包括每个元组中的主机[All]成员。

像这样

MEMBER [Languages].[Language].[All].[EUROPE] AS
    (
       [Languages].[Language].[All]
      ,[Stores].[Region].&[EUROPE]
    )
MEMBER [Languages].[Language].[All].[Japan] AS
    (
       [Languages].[Language].[All]
      ,[Stores].[Country].&[Japan]&[APAC]
    )  
MEMBER [Languages].[Language].[All].[China] AS
    (
       [Languages].[Language].[All]
      ,[Stores].[Country].&[China]&[APAC]
    )  
SET [S1] AS
   {
     [Languages].[Language].[All].[EUROPE]
    ,[Languages].[Language].[All].[Japan] 
    ,[Languages].[Language].[All].[China]
   }
MEMBER [Languages].[Language].[All].[Grand Total] AS
    Aggregate([S1])
SET [S2] AS
   {
     [Languages].[Language].[All].[EUROPE]
    ,[Languages].[Language].[All].[Japan] 
    ,[Languages].[Language].[All].[China]
    ,[Languages].[Language].[All].[Grand Total]
   } 

然后在脚本中试试这个

 [S2] ON ROWS