仅当URL变为LONG时，ORA-29263才会抛出错误

Posted 2021-05-04

我想从我的okg pkg拨打一份宁静的服务;有时使用相同的代码，成功到达此服务并返回响应;但是当url中的消息变得更长时==> ORA-29273 http请求和ORA-29263 http协议被抛出;我不会在通话之间改变任何内容，只会从此网址发送消息;以下是我的程序：

PROCEDURE SEND_SMS(username   VARCHAR2,
                   password   VARCHAR2,
                   phone      VARCHAR2,
                   message    VARCHAR2,
                   code       VARCHAR2,                 
                   P_RESPONSE OUT VARCHAR2) AS

    v_request         UTL_HTTP.req;
    v_response        UTL_HTTP.resp;
    v_text            VARCHAR2(1024);
    v_url             VARCHAR2(1024);
    v_message         VARCHAR2(1024);


  BEGIN
    BEGIN

      P_RESPONSE := '';
      v_message  := REPLACE(message,' ', '%20');


      v_url             := 'http://myservicelink.com/SendSMS?strUsername=' |
                           username || '&strPassword=' || password ||
                           '&strPhone=' || phone || '&strcode=' || code ||
                           '&strMessage=' || v_message;
      v_request         := UTL_HTTP.begin_request(v_url);

      DBMS_OUTPUT.put_line(v_url);

      v_response := UTL_HTTP.get_response(v_request);

      LOOP
        BEGIN
          UTL_HTTP.read_text(v_response, v_text);
          DBMS_OUTPUT.put_line(v_text);
        EXCEPTION
          WHEN UTL_HTTP.end_of_body THEN
            NULL;
        END;

        EXIT WHEN v_text IS NULL;
      END LOOP;

      UTL_HTTP.end_response(v_response);

      IF v_response.status_code <> 200 THEN
        P_RESPONSE := v_response.reason_phrase;
      END IF;

    EXCEPTION
      WHEN OTHERS THEN
       P_RESPONSE := 'An error has occured: ' || SQLERRM;
    END;

  END SEND_SMS;

因此，当v_message变长时，抛出异常。可能是什么错误;请注意，相同的链接从外部ORA pkg调用，具有相同的输入 - >到达myservice;

这是我工作信息的模板：Dear X, you have been registered to our app. You can download the app for iPhone at link of app store or for android at link of

不工作：Dear X, you have been registered to our app. You can download the app for iPhone at link of app store or for android at link of play store your

答案

你的两个字符串之间的区别不仅仅是长度;第二个也有一个换行符。您正在使用以下替换空格：

v_message  := REPLACE(message,' ', '%20');

但这不会涉及任何其他非法字符。

如果你改变它使用the utl_url.escape() function：

v_message  := utl_url.escape(message);

那么它也将逃脱新的行，所以你最终会得到第一条消息（与当前代码相同）：

Dear%20X,%20you%20have%20been%20registered%20to%20our%20app.%20You%20can%20download%20the%20app%20for%20iPhone%20at%20link%20of%20app%20store%20or%20for%20android%20at%20link%20of

但这是第二个：

Dear%20X,%20you%20have%20been%20registered%20to%20our%20app.%20You%20can%20download%20the%20app%20for%20iPhone%20at%20link%20of%20app%20store%20or%20for%20android%20at%20link%20of%20play%20store%0Ayour

换行符编码为%0A。根据消息中的其他内容，您可能需要将true作为第二个参数传递，而不是将其默认为false;差异在上面的文档链接中解释。