如果密钥的日期比今天的日期早N天，如何删除密钥？

Posted 2021-05-03

如果密钥的日期比今天的日期早N天，如何删除密钥？

假设我要删除所有比当前日期（5-6-2020）早2天以上的密钥，

原件：

{
  "player": {
    "1-6-2020=>1591023427": "5.4M",
    "2-6-2020=>1591125091": "5.21M",
    "3-6-2020=>1590947416": "3.07M",
    "4-6-2020=>1591023427": "2.95M",
    "5-6-2020=>1591125091": "2.93M"
  },
  "player2": {
    "1-6-2020=>1591023427": "5.4M",
    "2-6-2020=>1591125091": "5.21M",
    "3-6-2020=>1590947416": "3.07M",
    "4-6-2020=>1591023427": "2.95M",
    "5-6-2020=>1591125091": "2.93M"
  }
}

所需结果：

{
  "player": {
    "3-6-2020=>1590947416": "3.07M",
    "4-6-2020=>1591023427": "2.95M",
    "5-6-2020=>1591125091": "2.93M"
  },
  "player2": {
    "3-6-2020=>1590947416": "3.07M",
    "4-6-2020=>1591023427": "2.95M",
    "5-6-2020=>1591125091": "2.93M"
  }
}

答案

从字典中提取日期（这里我使用datetime模块的格式来提取它）

过滤掉距离太远的日子（为此使用内置过滤器的python内置函数）
1. 最终遍历玩家，并将此过滤器应用于玩家的字典

def filter_days_wrapper(n): n_days_back = n def filter_last_days(item): current_date = date.today() entry_date = datetime.strptime(item[0].split("=>")[0], '%d-%m-%Y') return current_date.day - entry_date.day <= n_days_back and current_date.month == entry_date.month and current_date.year == entry_date.year return filter_last_days

然后该调用应与过滤器函数一起消除日期：

for player in players:
    # used 2 for example, players is your dictionary
    players[player] = dict(filter(filter_days_wrapper(2), players[player].items()))