查询错误（1064）：'INTERSECT附近的语法错误（SELECT friend_id FROM user_friend_list WHERE user_id ='20'和

Posted 2021-05-03

(SELECT friend_id FROM user_friend_list WHERE user_id = '13' and 
`friend_id` in(select user_id from user_friend_list where friend_id='13' and `is_delete` = 'No') 
and is_delete = 'No')INTERSECT(SELECT friend_id FROM user_friend_list WHERE user_id = '20' and
friend_id in(select user_id from user_friend_list where friend_id='20' and is_delete = 'No') 
and is_delete = 'No');

答案

mysql中没有INTERSECT运算符。尝试使用INNER JOIN代替：

SELECT friend_id FROM
 (SELECT friend_id ...) T1
INNER JOIN
 (SELECT friend_id ... ) T2 
ON T1.friend_id = T2.friend_id;

另一答案

MySQL不支持INTERSECT运算符。但是，您可以模拟INTERSECT运算符。

这里有一个在MYSQL中模拟INTERSECT的操作指南：

http://www.mysqltutorial.org/mysql-intersect/