以周期为单位绘制刻度线

Posted 2021-05-03

我有一个包含4列的文件，其意思是，起点的坐标（x1，y1），终点的坐标（x2，y2）。我需要绘制许多连接这两个点的线。它具有不同的y值，x值是旁边的xtics数量。您能建议我一个在同一图中绘制这些线的周期吗？

2 11.6414 3 9.2395
3 9.23494 4 8.43797
3 9.2395 4 8.43797
1 6.46786 2 1.69241
1 8.76289 2 1.69241
1 8.76289 2 7.04954
2 11.6414 3 9.2395
3 9.2395 4 8.43797
4 10.3475 5 9.69117
4 10.7528 5 9.69117
4 10.7528 5 10.3576
4 11.0156 5 9.69117
5 11.199 6 11.021
1 6.46786 2 1.69241
1 8.76289 2 1.69241
4 11.3245 5 11.199
5 11.199 6 11.021
6 11.021 5 9.69117
6 11.021 5 10.3576

通知后我有

dfr = pd.read_csv('souradnice.csv')
dfr.columns = ['x1', 'y1', 'x2', 'y2']

dfr['dx'] = dfr.x2 - dfr.x1  # rozdíl x-ovových hodnot
dfr['dy'] = dfr.y2 - dfr.y1  # rozdíl y-ových hodnot

q = ax.quiver(dfr.x1, dfr.y1, dfr.dx, dfr.dy, units='xy', scale=1)
ax.set_aspect('equal')
plt.xlim(0, 6)
plt.ylim(0, 12)

答案

使用matplotlib.pyplot.quiver：

• 使用颤动需要计算matplotlib.pyplot.quiver和dx

dy

情节：

• 请查阅import pandas as pd df = pd.read_csv('souradnice.csv', header=None, names=['x1', 'y1', 'x2', 'y2'], dtype='float') # add sep=' ' if values are space separated df['dx'] = df.x2 - df.x1 df['dy'] = df.y2 - df.y1 x1 y1 x2 y2 dx dy 2 11.64140 3 9.23950 1 -2.40190 3 9.23494 4 8.43797 1 -0.79697 3 9.23950 4 8.43797 1 -0.80153 1 6.46786 2 1.69241 1 -4.77545 1 8.76289 2 1.69241 1 -7.07048 1 8.76289 2 7.04954 1 -1.71335 2 11.64140 3 9.23950 1 -2.40190 3 9.23950 4 8.43797 1 -0.80153 4 10.34750 5 9.69117 1 -0.65633 4 10.75280 5 9.69117 1 -1.06163 4 10.75280 5 10.35760 1 -0.39520 4 11.01560 5 9.69117 1 -1.32443 5 11.19900 6 11.02100 1 -0.17800 1 6.46786 2 1.69241 1 -4.77545 1 8.76289 2 1.69241 1 -7.07048 4 11.32450 5 11.19900 1 -0.12550 5 11.19900 6 11.02100 1 -0.17800 6 11.02100 5 9.69117 -1 -1.32983 6 11.02100 5 10.35760 -1 -0.66340 文档，因为有许多用于更改线条和箭头外观的参数。
• quiver

Advanced quiver and quiverkey functions

import matplotlib.pyplot as plt fig, ax = plt.subplots(figsize=(10, 10)) q = ax.quiver(df.x1, df.y1, df.dx, df.dy, units='xy', scale=1) plt.grid() ax.set_aspect('equal') plt.xlim(0, 6) plt.ylim(0, 12) plt.show()