将类序列化为XML并包括CDATA节的问题

Question 1

响应您在编辑后看到的'空格'，这是因为您使用的编码（Unicode，每个字符2个字节）。

Answer

响应您在编辑后看到的'空格'，这是因为您使用的编码（Unicode，每个字符2个字节）。

Question 2

对您有帮助吗？http://msdn.microsoft.com/en-us/library/system.xml.xmldocument.createcdatasection.aspx

//Create a CData section.
XmlCDataSection CData;
CData = doc.CreateCDataSection("All Jane Austen novels 25% off starting 3/23!");    

//Add the new node to the document.
XmlElement root = doc.DocumentElement;
root.AppendChild(CData);  

Console.WriteLine("Display the modified XML...");        
doc.Save(Console.Out);

Answer

对您有帮助吗？http://msdn.microsoft.com/en-us/library/system.xml.xmldocument.createcdatasection.aspx

//Create a CData section.
XmlCDataSection CData;
CData = doc.CreateCDataSection("All Jane Austen novels 25% off starting 3/23!");    

//Add the new node to the document.
XmlElement root = doc.DocumentElement;
root.AppendChild(CData);  

Console.WriteLine("Display the modified XML...");        
doc.Save(Console.Out);

Question 3

将ShipmentInfo作为IXmlSerializable类型实现将接近您所需要的-请参见下面的示例。

public class StackOverflow_11471676
{
    public class UpdateOrderStatus
    {
        public int Action { get; set; }
        public ValueInfo Value { get; set; }
    }
    [XmlType(TypeName = "Shipment")]
    public class ShipmentInfo
    {
        public string Header { get; set; }
        public string Body { get; set; }
    }
    public class ValueInfo : IXmlSerializable
    {
        public ShipmentInfo Shipment { get; set; }
        private XmlSerializer shipmentInfoSerializer = new XmlSerializer(typeof(ShipmentInfo));

        public System.Xml.Schema.XmlSchema GetSchema()
        {
            return null;
        }

        public void ReadXml(XmlReader reader)
        {
            using (MemoryStream ms = new MemoryStream(
                Encoding.UTF8.GetBytes(
                    reader.ReadContentAsString())))
            {
                Shipment = (ShipmentInfo)this.shipmentInfoSerializer.Deserialize(ms);
            }
        }

        public void WriteXml(XmlWriter writer)
        {
            using (MemoryStream ms = new MemoryStream())
            {
                using (XmlWriter innerWriter = XmlWriter.Create(ms, new XmlWriterSettings { OmitXmlDeclaration = true }))
                {
                    shipmentInfoSerializer.Serialize(innerWriter, this.Shipment);
                    innerWriter.Flush();
                    writer.WriteCData(Encoding.UTF8.GetString(ms.ToArray()));
                }
            }
        }
    }
    public static void Test()
    {
        UpdateOrderStatus obj = new UpdateOrderStatus
        {
            Action = 1,
            Value = new ValueInfo
            {
                Shipment = new ShipmentInfo
                {
                    Header = "Shipment header",
                    Body = "Shipment body"
                }
            }
        };

        XmlSerializer xs = new XmlSerializer(typeof(UpdateOrderStatus));
        MemoryStream ms = new MemoryStream();
        xs.Serialize(ms, obj);
        Console.WriteLine(Encoding.UTF8.GetString(ms.ToArray()));
    }
}

Answer

将ShipmentInfo作为IXmlSerializable类型实现将接近您所需要的-请参见下面的示例。

public class StackOverflow_11471676
{
    public class UpdateOrderStatus
    {
        public int Action { get; set; }
        public ValueInfo Value { get; set; }
    }
    [XmlType(TypeName = "Shipment")]
    public class ShipmentInfo
    {
        public string Header { get; set; }
        public string Body { get; set; }
    }
    public class ValueInfo : IXmlSerializable
    {
        public ShipmentInfo Shipment { get; set; }
        private XmlSerializer shipmentInfoSerializer = new XmlSerializer(typeof(ShipmentInfo));

        public System.Xml.Schema.XmlSchema GetSchema()
        {
            return null;
        }

        public void ReadXml(XmlReader reader)
        {
            using (MemoryStream ms = new MemoryStream(
                Encoding.UTF8.GetBytes(
                    reader.ReadContentAsString())))
            {
                Shipment = (ShipmentInfo)this.shipmentInfoSerializer.Deserialize(ms);
            }
        }

        public void WriteXml(XmlWriter writer)
        {
            using (MemoryStream ms = new MemoryStream())
            {
                using (XmlWriter innerWriter = XmlWriter.Create(ms, new XmlWriterSettings { OmitXmlDeclaration = true }))
                {
                    shipmentInfoSerializer.Serialize(innerWriter, this.Shipment);
                    innerWriter.Flush();
                    writer.WriteCData(Encoding.UTF8.GetString(ms.ToArray()));
                }
            }
        }
    }
    public static void Test()
    {
        UpdateOrderStatus obj = new UpdateOrderStatus
        {
            Action = 1,
            Value = new ValueInfo
            {
                Shipment = new ShipmentInfo
                {
                    Header = "Shipment header",
                    Body = "Shipment body"
                }
            }
        };

        XmlSerializer xs = new XmlSerializer(typeof(UpdateOrderStatus));
        MemoryStream ms = new MemoryStream();
        xs.Serialize(ms, obj);
        Console.WriteLine(Encoding.UTF8.GetString(ms.ToArray()));
    }
}

Question 4

下面的示例仅在定义了架构的结构并且您没有选择更改架构的选择时。

当您对[xmltext]]进行反序列化/序列化时，很难将文本保存在CDATA[]中括。您可以使用compiletransform照原样获取CDATA中的xml值，但是一旦在C＃中反序列化并加载到内存中，CDATA就会丢失。

Answer

下面的示例仅在定义了架构的结构并且您没有选择更改架构的选择时。

当您对[xmltext]]进行反序列化/序列化时，很难将文本保存在CDATA[]中括。您可以使用compiletransform照原样获取CDATA中的xml值，但是一旦在C＃中反序列化并加载到内存中，CDATA就会丢失。

Question 5

我认为carlosfigueira给出了一个很好的答案，但乍一看可能有点难以理解。这是您考虑的替代方法，可以分别对UpdateOrderStatus和ShipmentInfo进行序列化/反序列化。

将您的业务对象类定义为：

Answer

我认为carlosfigueira给出了一个很好的答案，但乍一看可能有点难以理解。这是您考虑的替代方法，可以分别对UpdateOrderStatus和ShipmentInfo进行序列化/反序列化。

将您的业务对象类定义为：

    [XmlRoot("UpdateOrderStatus")]
    public class UpdateOrderStatus
    {
        [XmlElement("Action")]
        public int Action { get; set; }

        private String valueField;
        [XmlElement("Value")]
        public XmlCDataSection Value
        {
            get
            {
                XmlDocument xmlDoc = new XmlDocument();
                return xmlDoc.CreateCDataSection(valueField);
            }
            set
            {
                this.valueField = value.Value;
            }
        }

        [XmlIgnore]
        public ShipmentInfo Shipment
        {
            get;
            set;
        }
    }

    [XmlRoot("ShipmentInfo")]
    public class ShipmentInfo
    {
        [XmlElement("Package")]
        public String Package { get; set; }
        [XmlElement("Header")]
        public String Header { get; set; }
    }

Answer 6

另一答案

Answer 7

另一答案

Answer 8

另一答案

Answer 9

另一答案