在数组（或ArrayList）中搜索由扫描仪用户指定的特定人（值），如果找到，则将该数组中的所有值返回/打印到扫描仪上

Question

我制作了带菜单的交互式扫描仪。在主菜单选项1中，我希望用户输入名称或数字，然后在我的数组或ArrayList中搜索该特定值。如果找到，我想返回同一数组中的所有值，并打印到扫描仪。

我一直在一天的大部分时间里努力完成这项工作。（请回答，就像您会成为新手一样）是我;）

我的主要：

        String[] employee1Array = {fitnessEmployee1.getName() + "       ", fitnessEmployee1.getCPR() + "   ", String.valueOf(fitnessEmployee1.getHours()) + "          ", String.valueOf(fitnessEmployee1.getSalary()) + "       ", fitnessEmployee1.getVacation()};
        String[] employee2Array = {fitnessEmployee2.getName() + "        ", fitnessEmployee2.getCPR() + "   ", String.valueOf(fitnessEmployee2.getHours()) + "          ", String.valueOf(fitnessEmployee2.getSalary()) + "      ", fitnessEmployee2.getVacation()};
        String[] employee3Array = {fitnessEmployee3.getName() + "        ", fitnessEmployee3.getCPR() + "   ", String.valueOf(fitnessEmployee3.getHours()) + "          ", String.valueOf(fitnessEmployee3.getSalary()) + "       ", fitnessEmployee3.getVacation()};
        String[] employee4Array = {fitnessEmployee4.getName() + "     ", fitnessEmployee4.getCPR() + "   ", String.valueOf(fitnessEmployee4.getHours()) + "          ", String.valueOf(fitnessEmployee4.getSalary()) + "      ", fitnessEmployee4.getVacation()};

        String[][] allEmployeesArray = {employee1Array,employee2Array,employee3Array,employee4Array};





        Scanner login = new Scanner(System.in);
        System.out.println("Please type in your username:");

        String userName = login.nextLine();
        if (userName.equals(userName1)) {
            System.out.println("Welcome " + userName);
        } else {

            System.out.println("Incorrect User - limited choices available");

        }


        String userChoice; 

        Scanner input = new Scanner(System.in);


        while(true){

            System.out.println("----Available Choices----");
            System.out.println(" Press 1 for search for a specific employee or member");
            System.out.println(" Press 2 to exit");

            System.out.println("
Please choose from the list:
");


            userChoice = input.next();

            String answer = "null";

            switch(userChoice){
                case "1":

                    System.out.println("Please write the name or CPR of the person you are searching for." );
                     answer = input.next();


                    System.out.println("Searching for " + answer);
                    for (int i = 0; i < allEmployeesArray.length; i++) {
                        System.out.println();

                            if (allEmployeesArray[i].equals(answer)) {
                                System.out.println(Arrays.toString(allEmployeesArray[i]));
                            }else{
                                System.out.println("Person not found");
                            }


                    }

                    System.out.println();
                    System.out.println("done with job number 1");
                    break;


                case "2":
                    //Afslut scanneren
                    System.out.println("Exiting...");
                    System.exit(0);
                default:

                    System.out.println("That is not a valid choice. Please try again...");
            }
        }



    }

}