插入后如何在datagridview中立即刷新或显示?
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将数据输入所有文本框后,单击提交按钮后,它不会立即显示在datagridview中,我需要重新打开表单才能看到新插入的行。要刷新什么代码?
跟着@ user3222297代码。通过添加grdPatient.Update();和grdPatient.Refresh();单击确定插入成功后仍然无法刷新。
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Data.SqlClient;
using System.Configuration;
namespace GRP_02_03_SACP
{
public partial class patient : Form
{
// Data Table to store employee data
DataTable Patient = new DataTable();
// Keeps track of which row in Gridview
// is selected
DataGridViewRow currentRow = null;
SqlDataAdapter PatientAdapter;
public patient()
{
InitializeComponent();
}
private void btnSubmit_Click(object sender, EventArgs e)
{
if (btnSubmit.Text == "Clear")
{
btnSubmit.Text = "Submit";
txtpFirstName.Focus();
}
else
{
btnSubmit.Text = "Clear";
int result = AddPatientRecord();
if (result > 0)
{
MessageBox.Show("Insert Successful");
grdPatient.Update();
grdPatient.Refresh();
}
else
MessageBox.Show("Insert Fail");
}
}
private int AddPatientRecord()
{
int result = 0;
// TO DO: Codes to insert customer record
//retrieve connection information info from App.config
string strConnectionString = ConfigurationManager.ConnectionStrings["sacpConnection"].ConnectionString;
//STEP 1: Create connection
SqlConnection myConnect = new SqlConnection(strConnectionString);
//STEP 2: Create command
String strCommandText = "INSERT PATIENT(pFirstName, pLastName, pContact, pAddress, pCity, pZip, pNationality, pRace, pIC, pGender, pDOB, pBloodType, pEmail) "
+ " VALUES (@pFirstName,@pLastName,@pContact,@pAddress,@pCity,@pZip,@pNationality, @pRace, @pIC, @pGender, @pDOB, @pBloodType, @pEmail)";
SqlCommand updateCmd = new SqlCommand(strCommandText, myConnect);
updateCmd.Parameters.AddWithValue("@pFirstName", txtpFirstName.Text);
updateCmd.Parameters.AddWithValue("@pLastName", txtpLastName.Text);
//updateCmd.Parameters["@clientid"].Direction = ParameterDirection.Output;
updateCmd.Parameters.AddWithValue("@pContact", txtpContact.Text);
updateCmd.Parameters.AddWithValue("@pAddress", txtpAddress.Text);
updateCmd.Parameters.AddWithValue("@pCity", txtpCity.Text);
updateCmd.Parameters.AddWithValue("@pZip", txtpZip.Text);
updateCmd.Parameters.AddWithValue("@pNationality", txtpNationality.Text);
updateCmd.Parameters.AddWithValue("@pRace", txtpRace.Text);
updateCmd.Parameters.AddWithValue("@pIC", txtpIC.Text);
updateCmd.Parameters.AddWithValue("@pGender", txtpGender.Text);
updateCmd.Parameters.AddWithValue("@pDOB", txtpDOB.Text);
updateCmd.Parameters.AddWithValue("@pBloodType", txtpBloodType.Text);
updateCmd.Parameters.AddWithValue("@pEmail", txtpEmail.Text);
// STEP 3 open connection and retrieve data by calling ExecuteReader
myConnect.Open();
// STEP 4: execute command
// indicates number of record updated.
result = updateCmd.ExecuteNonQuery();
// STEP 5: Close
myConnect.Close();
return result;
}
private void patient_Load(object sender, EventArgs e)
{
LoadPatientRecords();
}
private void LoadPatientRecords()
{
//retrieve connection information info from App.config
string strConnectionString = ConfigurationManager.ConnectionStrings["sacpConnection"].ConnectionString;
//STEP 1: Create connection
SqlConnection myConnect = new SqlConnection(strConnectionString);
//STEP 2: Create command
string strCommandText = "SELECT pFirstName, pLastName, pContact, pAddress, pCity, pZip, pNationality, pRace, pIC, pGender, pDOB, pBloodType, pEmail, pUsername, pPassword FROM Patient";
PatientAdapter = new SqlDataAdapter(strCommandText, myConnect);
//command builder generates Select, update, delete and insert SQL
// statements for MedicalCentreAdapter
SqlCommandBuilder cmdBuilder = new SqlCommandBuilder(PatientAdapter);
// Empty Employee Table first
Patient.Clear();
// Fill Employee Table with data retrieved by data adapter
// using SELECT statement
PatientAdapter.Fill(Patient);
// if there are records, bind to Grid view & display
if (Patient.Rows.Count > 0)
grdPatient.DataSource = Patient;
}
}
}
成功插入后使用LoadPatientRecords()
。
请尝试以下代码
private void btnSubmit_Click(object sender, EventArgs e)
{
if (btnSubmit.Text == "Clear")
{
btnSubmit.Text = "Submit";
txtpFirstName.Focus();
}
else
{
btnSubmit.Text = "Clear";
int result = AddPatientRecord();
if (result > 0)
{
MessageBox.Show("Insert Successful");
LoadPatientRecords();
}
else
MessageBox.Show("Insert Fail");
}
}
只需要像这样再次填充datagrid:
this.XXXTableAdapter.Fill(this.DataSet.XXX);
如果您使用从dataGridView自动连接此代码在Form_Load()中自动创建
尝试在每次插入后刷新datagrid
datagridview1.update();
datagridview1.refresh();
希望这对你有所帮助!
你可以将qazxsw poi qazxsw poi设置为qazxsw poi并再次绑定它。
datagridview
我不知道你是否解决了你的问题,但解决这个问题的一个简单方法是重建datagridview的DataSource(它是一个属性)。例如:
DataSource
在表单设计器中使用工具箱添加新计时器。在属性中将“已启用”设置为“True”。
null
将private void button1_Click(object sender, EventArgs e)
{
myAccesscon.ConnectionString = connectionString;
dataGridView.DataSource = null;
dataGridView.Update();
dataGridView.Refresh();
OleDbCommand cmd = new OleDbCommand(sql, myAccesscon);
myAccesscon.Open();
cmd.CommandType = CommandType.Text;
OleDbDataAdapter da = new OleDbDataAdapter(cmd);
DataTable bookings = new DataTable();
da.Fill(bookings);
dataGridView.DataSource = bookings;
myAccesscon.Close();
}
设置为等于计时器中的新数据
grdPatient.DataSource = MethodThatReturnList();
尝试下面的代码。
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