如何对重复数据的数组值求和

Posted 2021-04-17

我有一个数组有一些相同的ID值，如下所示。

[
    {"ID":"126871","total":"200.00","currency":"USD","name":"John"},
    {"ID":"126872","total":"2000.00","currency":"Euro","name":"John"},
    {"ID":"126872","total":"1000.00","currency":"Euro","name":"John"},
    {"ID":"126872","total":"500.00","currency":"USD","name":"John"},
    {"ID":"126872","total":"1000.00","currency":"Euro","name":"John"},
]

如果ID值重复，则将相同currency的总值相加。对于相同currency的不同ID，不需要总结total。

这就是我想要的。

[
    {"ID":"126871","total":"200.00","currency":"USD","name":"John"},
    {"ID":"126872","total":"4000.00","currency":"Euro","name":"John"},
    {"ID":"126872","total":"500.00","currency":"USD","name":"John"}
]

我遇到了上述问题。我已经尽力了。但是我得到了错误的结果。我非常感谢任何建议。

答案

@Cloud我已根据您的要求制作了功能并感谢@M。 I.查看这个总和部分。

$array = array(
    array("ID"  => "126871","total"=>"200.00","currency"=>"USD","name"=>"John"),
    array("ID"  => "126872","total"=>"2000.00","currency"=>"Euro","name"=>"John"),
    array("ID"  => "126872","total"=>"1000.00","currency"=>"Euro","name"=>"John"),
    array("ID"  => "126872","total"=>"500.00","currency"=>"USD","name"=>"John"),
    array("ID"  => "126872","total"=>"1000.00","currency"=>"Euro","name"=>"John"),
);
echo "<pre>";
print_r($array);

function unique_multidim_array($array, $key,$key1,$addedKey) { 
    $temp_array = array(); 
    $i = 0; 
    $key_array = array(); 
    $key1_array = array(); 

    foreach($array as $val) { 
        if (!in_array($val[$key], $key_array) && !in_array($val[$key1], $key1_array)) { 
            $key_array[$i] = $val[$key]; 
            $key1_array[$i] = $val[$key1]; 
            $temp_array[$i] = $val; 
        }else{
            $pkey = array_search($val[$key],$key_array);
            $pkey1 = array_search($val[$key1],$key1_array);
            if($pkey==$pkey1){
                $temp_array[$pkey][$addedKey] += $val[$addedKey];
            }else{
                $key_array[$i] = $val[$key]; 
                $key1_array[$i] = $val[$key1]; 
                $temp_array[$i] = $val; 
            }
            // die;
        }
        $i++; 
    } 
    return $temp_array; 
} 

$nArray = unique_multidim_array($array,"ID","currency","total");
// die;
print_r($nArray);
die;

另一答案

@Cloud试试这个。

$array = array(array("ID"   => "126871","total"=>"200.00","currency"=>"USD","name"=>"John",),array("ID" => "126871","total"=>"200.00","currency"=>"USD","name"=>"John",),array("ID" => "126872","total"=>"1000.00","currency"=>"Euro","name"=>"John",));
    echo "<pre>";
    print_r($array);
    $unique = array_map('unserialize', array_unique(array_map('serialize', $array)));

当然@Magnus Eriksson。我在解释为​​什么我们在步骤中使用'serialize'和'unserialize'：

第1步：将多维数组转换为一维数组

要将多维数组转换为一维数组，首先要生成数组内所有元素（包括嵌套数组）的字节流表示。 serialize（）函数可以生成一个值的字节流表示。要生成所有元素的字节流表示，请在serialize()函数内调用array_map()函数作为回调函数。无论多维数组有多少级别，结果都将是一维数组。

第2步：使值唯一

要使这个一维数组唯一，请使用array_unique()函数。

第3步：将其还原为多维数组

虽然数组现在是唯一的，但值看起来像字节流表示。要将其还原为多维数组，请使用unserialize()函数。

我希望我为什么要制作这段代码。

另一答案

内容：创建按“ID”和“货币”分组的数组。累计重复货币。

怎么样：

• 一次添加一行到输出数组。
• 如果group不在数组中，则添加它
• 如果它在数组中，则将货币添加到现有记录中。

Demonstration at eval.in

码：

/** ----------------------------------------------
* Create an output array one row at a time.
* 
* Group by Id and currency.   
* 
* @param array $groups
* 
* @return array
*/
function getCurrencyGroups(array $groups)
{
    $currencyGroups = array();

    foreach ($groups as $item) {

        $id       = $item['ID'];
        $currency = $item['currency'];
        $amount   = $item['total'];

        if (!isset($currencyGroups[$id][$currency])) {
            $currencyGroups[$id][$currency] = $amount;
        }
        else {
            $currencyGroups[$id][$currency] += $amount;
        }
    }

    return $currencyGroups;
}

运行：

$currencyGroups = getCurrencyGroups($source);

输出：

array (size=2)
  126871 => 
    array (size=1)
      'USD' => string '200.00' (length=6)

  126872 => 
    array (size=2)
      'Euro' => float 4000
      'USD' => string '500.00' (length=6)

另一答案

你需要：

• 使用json_decode将您的json字符串转换为php数组。
• 循环遍历行并使用复合临时键对它们进行分组。换句话说，从每行的ID和currency值生成一个字符串，并将该字符串用作临时唯一键。
• 对分组行的total值求和。
• 然后通过重新索引行并调用json_encode()来准备输出数组以返回到json。

代码：（Demo）

$json='[
    {"ID":"126871","total":"200.00","currency":"USD","name":"John"},
    {"ID":"126872","total":"2000.00","currency":"Euro","name":"John"},
    {"ID":"126872","total":"1000.00","currency":"Euro","name":"John"},
    {"ID":"126872","total":"500.00","currency":"USD","name":"John"},
    {"ID":"126872","total":"1000.00","currency":"Euro","name":"John"}
]';

$array=json_decode($json,true);  // convert to array
foreach($array as $row){
    if(!isset($result[$row['ID'].$row['currency']])){
        $result[$row['ID'].$row['currency']]=$row;  // on first occurrence, store the full row
    }else{
        $result[$row['ID'].$row['currency']]['total']+=$row['total'];  // after first occurrence, add current total to stored total
    }
}
$result=json_encode(array_values($result));  // reindex the array and convert to json
echo $result;  // display

输出：

[
    {"ID":"126871","total":"200.00","currency":"USD","name":"John"},
    {"ID":"126872","total":4000,"currency":"Euro","name":"John"},
    {"ID":"126872","total":"500.00","currency":"USD","name":"John"}
]