lambda去重

Posted 2023-04-05

参考技术A lambda去重使用collectingAndThen方法
list<Object> 对象中,如果根据Object的单个属性进行过滤去重,
则: List<User> userList = users.stream() .collect(

        Collectors.collectingAndThen(Collectors.toCollection(() -> new TreeSet<>(Comparator.comparing(user ->  user.getName()))), ArrayList::new));

如果是根据Object中的多个对象,则:
List<User> userList = users.stream() .collect(

        Collectors.collectingAndThen(

                Collectors.toCollection(() -> new TreeSet<>(Comparator.comparing(user -> user.getName()+";"+user.getId()))), ArrayList::new));

List去重两个相同的实体类对象或者相同的单个对象字段

java对list集合进行去重 传统方式 VS Lambda

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把下面代码放到模板你想显示的位置

{dede:field.keywords runphp=yes}
global $dsql,$id,$aid;
$aid = isset($id) ? $id : $aid;
$keyword = ‘‘;
if(!empty(@me))
{
    $keywords = explode(‘,‘ , trim(@me));
    $keyword = ‘‘;
    $n = 1;
    foreach($keywords as $k)
    {
        if($n > 3)  break;
        
        if(trim($k)==‘‘) continue;
        else $k = addslashes($k);
        
        $keyword .= ($keyword==‘‘ ? " CONCAT(arc.keywords,‘ ‘,arc.title) LIKE ‘%$k%‘ " : " OR CONCAT(arc.keywords,‘ ‘,arc.title) LIKE ‘%$k%‘ ");
        $n++;
    }
}
if($keyword != ‘‘)
{
    $sql = "SELECT arc.*,tp.typedir,tp.typename,tp.corank,tp.isdefault,tp.defaultname,tp.namerule,tp.namerule2,tp.ispart,tp.moresite,tp.siteurl,tp.sitepath FROM `#@__archives` arc LEFT JOIN `#@__arctype` tp ON arc.typeid=tp.id where arc.arcrank>-1 AND ($keyword) AND arc.id<>‘$aid‘ ORDER BY arc.id desc limit 0, 10";
}

$dsql->SetQuery($sql);
$dsql->Execute(‘t‘);
$result = ‘‘;
while($row = $dsql->GetArray(‘t‘))
{
	$arcrow = GetOneArchive($row[‘id‘]);
	$row[‘arcurl‘] = $arcrow[‘arcurl‘];
	$row[‘pubdate‘] = MyDate(‘Y-m-d‘,$row[‘pubdate‘]);
	$row[‘litpic‘] = $row[‘litpic‘] = $row[‘litpic‘]==‘‘ ? ‘/images/defaultpic.gif‘ : $row[‘litpic‘];
	$result .= "<li><a href="{$row[‘arcurl‘]}"><img src="{$row[‘litpic‘]}">{$row[‘title‘]}</a></li>";
}
@me = $result;
{/dede:field.keywords}