GSON将布尔值序列化为0或1

Posted 2021-04-10

所有，

我正在尝试执行以下操作：

public class SomClass
{
    public boolean x;
    public int y;
    public String z;
}       

SomClass s = new SomClass();
s.x = true;
s.y = 10;
s.z = "ZZZ";
Gson gson = new Gson();
String retVal = gson.toJson(s);
return retVal;

所以这个小片段会产生：

{"x":true,"y":10,"z":"ZZZ"}

但我需要它生产的是：

{"x":0, "y":10,"z":"ZZZ"}

有人可以给我一些选择吗？我不希望将我的布尔值重写为整数，因为这将导致现有代码存在若干问题（非显而易见，难以阅读，难以执行等）

答案

为了使其“正确”，您可以使用类似的东西

import java.lang.reflect.Type;

import com.google.gson.JsonDeserializationContext;
import com.google.gson.JsonDeserializer;
import com.google.gson.JsonElement;
import com.google.gson.JsonParseException;
import com.google.gson.JsonPrimitive;
import com.google.gson.JsonSerializationContext;
import com.google.gson.JsonSerializer;

public class BooleanSerializer implements JsonSerializer<Boolean>, JsonDeserializer<Boolean> {

    @Override
    public JsonElement serialize(Boolean arg0, Type arg1, JsonSerializationContext arg2) {
        return new JsonPrimitive(Boolean.TRUE.equals(arg0));
    }

    @Override
    public Boolean deserialize(JsonElement arg0, Type arg1, JsonDeserializationContext arg2) throws JsonParseException {
        return arg0.getAsInt() == 1;
    }
}

然后使用它：

public class Main {

    public class Base {
        @Expose
        @SerializedName("class")
        protected String clazz = getClass().getSimpleName();
        protected String control = "ctrl";
    }

    public class Child extends Base {
        protected String text = "This is text";
        protected Boolean boolTest = false;
    }

    /**
     * @param args
     */
    public static void main(String[] args) {
        Main m = new Main();
        GsonBuilder b = new GsonBuilder();
        BooleanSerializer serializer = new BooleanSerializer();
        b.registerTypeAdapter(Boolean.class, serializer);
        b.registerTypeAdapter(boolean.class, serializer);
        Gson gson = b.create();

        Child c = m.new Child();
        System.out.println(gson.toJson(c));
        String testStr = "{"text":"This is text","boolTest":1,"class":"Child","control":"ctrl"}";
        Child cc = gson.fromJson(testStr, Main.Child.class);
        System.out.println(gson.toJson(cc));
    }
}

希望这有助于某人:-)

另一答案

或者：Gson User Guide - Custom Serialization and Deserialization