排球图库忽略格式= feed＆type = rss Params

Question

我需要使用Volley库获取rss feed但是Volley一直忽略我的format=feed&type=rss Params。我尝试了所有的东西，但我无法让它工作。这是我的网址：http://almesryoon.com/%D8%AF%D9%81%D8%AA%D8%B1-%D8%A3%D8%AD%D9%88%D8%A7%D9%84-%D8%A7%D9%84%D9%88%D8%B7%D9%86?format=feed&type=rss 注意：此网址适用于Google PostMan 我的SimpleXmlRequest课程：

public class SimpleXmlRequest<T> extends Request<T> {

    private static final Serializer serializer = new Persister();
    private final Class<T> clazz;
    private final Map<String, String> headers;
    private final Listener<T> listener;


    /**
     * Make HTTP request and return a parsed object from Response
     * Invokes the other constructor.
     *
     * @see SimpleXmlRequest#SimpleXmlRequest(int, String, Class, Map, Listener, ErrorListener)
     */
    public SimpleXmlRequest(int method, String url, Class<T> clazz,
                            Listener<T> listener, ErrorListener errorListener) {
        this(method, url, clazz, null, listener, errorListener);
    }


    /**
     * Make HTTP request and return a parsed object from XML Response
     *
     * @param url URL of the request to make
     * @param clazz Relevant class object
     * @param headers Map of request headers
     * @param listener
     * @param errorListener
     *
     */
    public SimpleXmlRequest(int method, String url, Class<T> clazz, Map<String, String> headers,
                            Listener<T> listener, ErrorListener errorListener) {
        super(method, url, errorListener);
        this.clazz = clazz;
        this.headers = headers;
        this.listener = listener;
    }


    @Override
    public Map<String, String> getHeaders() throws AuthFailureError {
        return headers != null ? headers : super.getHeaders();
    }


    @Override
    protected void deliverResponse(T response) {
        listener.onResponse(response);
    }

    @Override
    public String getBodyContentType() {
        return "application/xml";
    }

    @Override
    protected Response<T> parseNetworkResponse(NetworkResponse response)
    {
        try {

            String data = new String(response.data, HttpHeaderParser.parseCharset(response.headers));// The problem here this data is not XML

            return Response.success(serializer.read(clazz, data),
                    HttpHeaderParser.parseCacheHeaders(response));
        }
        catch (UnsupportedEncodingException e) {
            return Response.error(new ParseError(e));
        }
        catch (Exception e) {
            return Response.error(new VolleyError(e.getMessage()));
        }
    }
}

此外，我试图使用METHOD.POST与getParams()方法目标rss：

<?xml version="1.0" encoding="utf-8"?>
<!-- generator="Joomla! - Open Source Content Management" -->
<rss version="2.0" 
    xmlns:atom="http://www.w3.org/2005/Atom">
    <channel>
        <title>Title</title>
        <description>Description</description>
        <link>http://google.com</link>
        <lastBuildDate>Thu, 31 Mar 2016 01:27:12 +0200</lastBuildDate>
        <generator>Joomla! - Open Source Content Management</generator>
        <atom:link rel="self" type="application/rss+xml" href="http://example.com/example?format=feed&amp;type=rss"/>
        <language>ar-aa</language>
        <item>
            <title>Item1</title>
            <link>http://example.com/example1</link>
            <guid isPermaLink="true">http://example.com/example1</guid>
            <description>Description1</description>
            <author>admin</author>
            <category>Category1</category>
            <pubDate>Wed, 30 Mar 2016 18:49:37 +0200</pubDate>
        </item>
        <item>
            <title>Item2</title>
            <link>http://example.com/example2</link>
            <guid isPermaLink="true">http://example.com/example2</guid>
            <description>Description2</description>
            <author>admin</author>
            <category>Category1</category>
            <pubDate>Wed, 30 Mar 2016 18:49:37 +0200</pubDate>
        </item>
    </channel>
</rss>

我正在使用这个代码并且它工作得很好但是HttpParams，BasicHttpParams，HttpConnectionParams，DefaultHttpClient，HttpGet，HttpResponse和HttpEntity现在已被弃用。我的工作代码：

StringBuilder chaine = new StringBuilder("");

        try {

            HttpParams httpParameters = new BasicHttpParams();
            // Set the timeout in milliseconds until a connection is established.
            // The default value is zero, that means the timeout is not used.
            int timeoutConnection = AppConstants.CONNECTION_TIMEOUT_SEC * 1000;
            HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
            // Set the default socket timeout (SO_TIMEOUT)
            // in milliseconds which is the timeout for waiting for data.
            int timeoutSocket = AppConstants.SOCKET_TIMEOUT_SEC * 1000;
            HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);

            // request method is GET
            DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
            HttpGet httpGet = new HttpGet(url);

            HttpResponse httpResponse = httpClient.execute(httpGet);
            HttpEntity httpEntity = httpResponse.getEntity();

            InputStream inputStream = httpEntity.getContent();

            BufferedReader rd = new BufferedReader(new InputStreamReader(inputStream));

            String line;

            while ((line = rd.readLine()) != null) {

                chaine.append(line);

            }

            rd.close();

        } catch (IOException e) {
            // writing exception to log
            e.printStackTrace();
        }

Answer 1

另一答案