无法将子进程发送回父进程的消息

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我试图了解管道和分叉是如何工作的。所以我编写了一个简单的程序,其中父进程向子进程发送消息(工作正常)。但是,如果我尝试通过添加注释代码从子进程发回消息,它将停止工作。输出“Parent sent:hello”后程序的执行停止。

int main() {
    int child_to_parent[2];
    int parent_to_child[2];
    pipe(child_to_parent);
    pipe(parent_to_child);

    pid_t id = fork();

    if (id == 0) {
        close(parent_to_child[1]);
        close(child_to_parent[0]);
        FILE* out = fdopen(child_to_parent[1], "w");
        FILE* in = fdopen(parent_to_child[0], "r");

        char msg[6];
        fscanf(in ,"%s", msg);
        printf("Child got: %s
", msg);
        /*
        fprintf(out, "hi ");
        printf("Child sent: hi
"); 
        */
    } else {
        close(parent_to_child[0]);
        close(child_to_parent[1]);
        FILE* in = fdopen(child_to_parent[0], "r");
        FILE* out = fdopen(parent_to_child[1], "w");

        fprintf(out, "hello");
        printf("Parent sent: hello
");
        /*
        char msg[3];
        fscanf(in, "%s", msg);
        printf("Parent got: %s
", msg);
        */
    }
}

我无法弄清楚原因。令我困惑的是为什么在修改代码后子进程甚至无法接收消息。谁能告诉我什么是错的,或者指引我朝着正确的方向前进?

答案

第一种使用读/写交换任意数量消息的解​​决方案

在这里,我指出要通过 n读取的每个缓冲区的结尾:

#include <stdio.h>
#include <unistd.h>
#include <string.h>

void rd(int fd, int child)
{
  char c;
  int first = 1;

  do {
    if (!read(fd, &c, 1))
      break;
    if (first) {
      printf("%s got:", (child) ? "Child" : "Parent");
      first = 0;
    }
    putchar(c);
  } while (c != '
');
}

void wr(int fd, const char * msg, int child)
{
  write(fd, msg, strlen(msg));
  printf("%s sent:%s", (child) ? "Child" : "Parent", msg);
}

int main() {
    int child_to_parent[2];
    int parent_to_child[2];

    pipe(child_to_parent);
    pipe(parent_to_child);

    pid_t id = fork();

    if (id == 0) {
      close(parent_to_child[1]);
      close(child_to_parent[0]);

      rd(parent_to_child[0], 1);
      wr(child_to_parent[1], "hi
", 1);

      rd(parent_to_child[0], 1);
      wr(child_to_parent[1], "fine, and you ?
", 1);

      rd(parent_to_child[0], 1);
    } else {
      close(parent_to_child[0]);
      close(child_to_parent[1]);

      wr(parent_to_child[1], "hello
", 0);
      rd(child_to_parent[0], 0);

      wr(parent_to_child[1], "how are you ?
", 0);
      rd(child_to_parent[0], 0);

      wr(parent_to_child[1], "fine too
", 0);
    }
}

编译和执行:

pi@raspberrypi:/tmp $ gcc -pedantic -Wextra p.c
pi@raspberrypi:/tmp $ ./a.out 
Parent sent:hello
Child got:hello
Child sent:hi
Parent got:hi
Parent sent:how are you ?
Child got:how are you ?
Child sent:fine, and you ?
Parent got:fine, and you ?
Parent sent:fine too
Child got:fine too

也可以使用fread / fwrite,在fwrite之后fflush是必要的,不被阻止。幸运的是,发送后无需关闭管道以便能够读取和回答,否则只能交换一条消息。我仍然使用 n来表示发送缓冲区的结尾:

#include <stdio.h>
#include <unistd.h>
#include <string.h>

void rd(FILE * fd, int child)
{
  char c;
  int first = 1;

  do {
    if (!fread(&c, 1, 1, fd))
      break;
    if (first) {
      printf("%s got:", (child) ? "Child" : "Parent");
      first = 0;
    }
    putchar(c);
  } while (c != '
');
}

void wr(FILE *  fd, const char * msg, int child)
{
  fwrite(msg, strlen(msg), 1, fd);
  fflush(fd);
  printf("%s sent:%s", (child) ? "Child" : "Parent", msg);
}

int main() {
    int child_to_parent[2];
    int parent_to_child[2];
    pipe(child_to_parent);
    pipe(parent_to_child);

    pid_t id = fork();

    if (id == 0) {
        close(parent_to_child[1]);
        close(child_to_parent[0]);
        FILE* out = fdopen(child_to_parent[1], "w");
        FILE* in = fdopen(parent_to_child[0], "r");

    rd(in, 1);
    wr(out, "hi
", 1);

    rd(in, 1);
    wr(out, "fine, and you ?
", 1);

    rd(in, 1);
    } else {
        close(parent_to_child[0]);
        close(child_to_parent[1]);
        FILE* in = fdopen(child_to_parent[0], "r");
        FILE* out = fdopen(parent_to_child[1], "w");

    wr(out, "hello
", 0);
    rd(in, 0);

    wr(out, "how are you ?
", 0);
    rd(in, 0);

    wr(out, "fine too
", 0);
    }
}

编译和执行:

pi@raspberrypi:/tmp $ gcc -pedantic -Wextra pp.c
pi@raspberrypi:/tmp $ ./a.out
Parent sent:hello
Child got:hello
Child sent:hi
Parent got:hi
Parent sent:how are you ?
Child got:how are you ?
Child sent:fine, and you ?
Parent got:fine, and you ?
Parent sent:fine too
Child got:fine too

最后,如果你想使用fscanf("%s", ...),你需要在单词之后发送一个分隔符(例如空格或 n)来阻止fscanf,当然还要读取分隔符,fflrite之后需要fflush。

如果我改变了一点你编程:

#include <stdio.h>
#include <unistd.h>

int main() {
    int child_to_parent[2];
    int parent_to_child[2];
    pipe(child_to_parent);
    pipe(parent_to_child);

    pid_t id = fork();

    if (id == 0) {
      close(parent_to_child[1]);
      close(child_to_parent[0]);
      FILE* out = fdopen(child_to_parent[1], "w");
      FILE* in = fdopen(parent_to_child[0], "r");
      char msg[16], c;

      fscanf(in ,"%s%c", msg, &c);
      printf("Child got: %s
", msg);

      fprintf(out, "hi ");
      fflush(out);
      printf("Child sent: hi
"); 

      fscanf(in ,"%s%c", msg, &c);
      printf("Child got: %s
", msg);

      fprintf(out, "fine,you? ");
      fflush(out);
      printf("Child sent: fine,you?
"); 

      fscanf(in ,"%s%c", msg, &c);
      printf("Child got: %s
", msg);
    } else {
      close(parent_to_child[0]);
      close(child_to_parent[1]);
      FILE* in = fdopen(child_to_parent[0], "r");
      FILE* out = fdopen(parent_to_child[1], "w");

      fprintf(out, "hello
");
      fflush(out);
      printf("Parent sent: hello
");

      char msg[16], c;

      fscanf(in, "%s%c", msg, &c);
      printf("Parent got: %s
", msg);

      fprintf(out, "how-are-you? ");
      fflush(out);
      printf("Parent sent: how-are-you?
");

      fscanf(in, "%s%c", msg, &c);
      printf("Parent got: %s
", msg);

      fprintf(out, "fine-too ");
      fflush(out);
      printf("Parent sent: fine-too
");
    }
}

编译和执行:

pi@raspberrypi:/tmp $ gcc -pedantic -Wextra ppp.c
pi@raspberrypi:/tmp $ ./a.out
Parent sent: hello
Child got: hello
Child sent: hi
Parent got: hi
Parent sent: how-are-you?
Child got: how-are-you?
Child sent: fine,you?
Parent got: fine,you?
Parent sent: fine-too
Child got: fine-too
另一答案

fscanf读取,直到你使用isspace找到一些空白字符(由%s给出),但你没有发送一个。所以fscanf永远不会回来,因为它正在等待空白。

使用freadfwrite而不是fscanffprintf,你的管道将起作用。

另一答案

在父级和子级中,当您完成对管道的写入后,使用fflush刷新缓冲区并使用close关闭管道写入结束。

这是一个略微修改的程序:

#include <sys/types.h>
#include <unistd.h>
#include <stdio.h>

FILE *fdopen(int fd, const char *mode);

int main() {
    int child_to_parent[2];
    int parent_to_child[2];
    pipe(child_to_parent);
    pipe(parent_to_child);

    pid_t id = fork();

    if (id == 0) {
        close(parent_to_child[1]);
        close(child_to_parent[0]);
        FILE* out = fdopen(child_to_parent[1], "w");
        FILE* in = fdopen(parent_to_child[0], "r");

        char msg[6];
        printf("Child gonna read...
");
        fscanf(in ,"%s", msg);
        printf("Child got: %s
", msg);

        fprintf(out, "hi");
        fflush(out);
        printf("Child sent: hi
");
        close(child_to_parent[1]);
    } else {
        close(parent_to_child[0]);
        close(child_to_parent[1]);
        FILE* in = fdopen(child_to_parent[0], "r");
        FILE* out = fdopen(parent_to_child[1], "w");

        fprintf(out, "hello");
        printf("Parent sent: hello
");
        fflush(out);
        close(parent_to_child[1]);

        char msg[3];
        printf("Parent gonna read...
");
        fscanf(in, "%s", msg);
        printf("Parent got: %s
", msg);
    }
}

运行时的输出:

Parent sent: hello
Parent gonna read...
Child gonna read...
Child got: hello
Child sent: hi
Parent got: hi

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