如何在Docker命令行上的Docker注册表中找到具有特定标记的Docker镜像？
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我尝试找到Docker镜像的一个特定标签。我怎么能在命令行上这样做？我尽量避免全部下载并删除不需要的图像。
在官方的Ubuntu版本中，https://registry.hub.docker.com/_/ubuntu/，有几个标签（发布它），而当我在命令行上搜索它时，
user@ubuntu:~$ docker search ubuntu | grep ^ubuntu
ubuntu Official Ubuntu base image 354
ubuntu-upstart Upstart is an event-based replacement for ... 7
ubuntufan/ping 0
ubuntu-debootstrap 0
在命令行search https://docs.docker.com/engine/reference/commandline/search/的帮助下，不知道它是如何工作的？
是否有可能在docker search命令？
如果我使用原始命令通过Docker registry API进行搜索，则可以获取信息：
$ curl https://registry.hub.docker.com//v1/repositories/ubuntu/tags | python -mjson.tool
[
{
"layer": "ef83896b",
"name": "latest"
},
.....
{
"layer": "463ff6be",
"name": "raring"
},
{
"layer": "195eb90b",
"name": "saucy"
},
{
"layer": "ef83896b",
"name": "trusty"
}
]
答案
据我所知，CLI不允许在存储库中搜索/列出标签。
但是如果你知道你想要哪个标签，你可以通过添加冒号和图像名称来明确地提取它：docker pull ubuntu:saucy
另一答案
您可以使用Visual Studio Code为可用的泊坞窗图像和标签提供自动完成功能。但是，这需要您键入标记的第一个字母才能看到自动填充建议。
例如，当写FROM ubuntu时，它提供自动填充建议，如ubuntu，ubuntu-debootstrap和ubuntu-upstart。在写FROM ubuntu:a时，它提供了像ubuntu:artful和ubuntu:artful-20170511.1这样的自动完成建议
另一答案
使用CoreOS时，jq可用于解析JSON数据。
就像你以前一样，看着library/centos
$ curl -s -S 'https://registry.hub.docker.com/v2/repositories/library/centos/tags/' | jq '."results"[]["name"]' |sort
"6"
"6.7"
"centos5"
"centos5.11"
"centos6"
"centos6.6"
"centos6.7"
"centos7.0.1406"
"centos7.1.1503"
"latest"
更干净的v2 API现在可用，这就是我在示例中使用的内容。我将构建一个简单的脚本docker_remote_tags：
#!/usr/bin/bash
curl -s -S "https://registry.hub.docker.com/v2/repositories/library/$@/tags/" | jq '."results"[]["name"]' |sort
启用：
$ ./docker_remote_tags library/centos
"6"
"6.7"
"centos5"
"centos5.11"
"centos6"
"centos6.6"
"centos6.7"
"centos7.0.1406"
"centos7.1.1503"
"latest"
参考：
jq：https://stedolan.github.io/jq/ | apt-get install jq
另一答案
此脚本（docker-show-repo-tags.sh）适用于任何支持curl，sed，grep和sort的支持Docker的主机。这已更新，以反映存储库标记URL已更改的事实。
#!/bin/sh
#
# Simple script that will display Docker repository tags
# using basic tools: curl, sed, grep, and sort.
#
# Usage:
# $ docker-show-repo-tags.sh ubuntu centos
for Repo in $* ; do
curl -sS "https://hub.docker.com/r/library/$Repo/tags/" |
sed -e $'s/"tags":/\
"tags":/g' -e $'s/]/\
]/g' |
grep '^"tags"' |
grep '"library"' |
sed -e $'s/,/,\
/g' -e 's/,//g' -e 's/"//g' |
grep -v 'library:' |
sort -fu |
sed -e "s/^/${Repo}:/"
done
这个旧版本不再有效。
#!/bin/sh
# WARNING: This no long works!
# Simple script that will display Docker repository tags.
#
# Usage:
# $ docker-show-repo-tags.sh ubuntu centos
for Repo in $* ; do
curl -s -S "https://registry.hub.docker.com/v2/repositories/library/$Repo/tags/" |
sed -e $'s/,/,\
/g' -e $'s/[/\[
/g' |
grep '"name"' |
awk -F" '{print $4;}' |
sort -fu |
sed -e "s/^/${Repo}:/"
done
这是一个简单示例的输出：
$ docker-show-repo-tags.sh centos | cat -n
1 centos:5
2 centos:5.11
3 centos:6
4 centos:6.10
5 centos:6.6
6 centos:6.7
7 centos:6.8
8 centos:6.9
9 centos:7.0.1406
10 centos:7.1.1503
11 centos:7.2.1511
12 centos:7.3.1611
13 centos:7.4.1708
14 centos:7.5.1804
15 centos:centos5
16 centos:centos5.11
17 centos:centos6
18 centos:centos6.10
19 centos:centos6.6
20 centos:centos6.7
21 centos:centos6.8
22 centos:centos6.9
23 centos:centos7
24 centos:centos7.0.1406
25 centos:centos7.1.1503
26 centos:centos7.2.1511
27 centos:centos7.3.1611
28 centos:centos7.4.1708
29 centos:centos7.5.1804
30 centos:latest
另一答案
我不喜欢上面的任何解决方案，因为A）他们需要我没有并且不想安装的外部库。 B）我没有得到所有的页面。
Docker API将每个请求限制为100个项目。这将循环遍历每个“下一个”项目并获取它们全部（对于Python它的7页;其他可能或多或少...取决于）
如果您真的想要自己发送垃圾邮件，请从最后一行删除| cut -d '-' -f 1，您将看到绝对的一切。
url=https://registry.hub.docker.com/v2/repositories/library/redis/tags/?page_size=100 `# Initial url` ;
(
while [ ! -z $url ]; do `# Keep looping until the variable url is empty`
>&2 echo -n "." `# Every iteration of the loop prints out a single dot to show progress as it got through all the pages (this is inline dot)` ;
content=$(curl -s $url | python -c 'import sys, json; data = json.load(sys.stdin); print(data.get("next", "") or ""); print("
".join([x["name"] for x in data["results"]]))') `# Curl the URL and pipe the output to Python. Python will parse the JSON and print the very first line as the next URL (it will leave it blank if there are no more pages) then continue to loop over the results extracting only the name; all will be stored in a variable called content` ;
url=$(echo "$content" | head -n 1) `# Let's get the first line of content which contains the next URL for the loop to continue` ;
echo "$content" | tail -n +2 `# Print the content without the first line (yes +2 is counter intuitive)` ;
done;
>&2 echo `# Finally break the line of dots` ;
) | cut -d '-' -f 1 | sort --version-sort | uniq;
样本输出：
$ url=https://registry.hub.docker.com/v2/repositories/library/redis/tags/?page_size=100 `#initial url` ;
> (
> while [ ! -z $url ]; do `#Keep looping until the variable url is empty`
> >&2 echo -n "." `#Every iteration of the loop prints out a single dot to show progress as it got through all the pages (this is inline dot)` ;
> content=$(curl -s $url | python -c 'import sys, json; data = json.load(sys.stdin); print(data.get("next", "") or ""); print("
".join([x["name"] for x in data["results"]]))') `# Curl the URL and pipe the JSON to Python. Python will parse the JSON and print the very first line as the next URL (it will leave it blank if there are no more pages) then continue to loop over the results extracting only the name; all will be store in a variable called content` ;
> url=$(echo "$content" | head -n 1) `#Let's get the first line of content which contains the next URL for the loop to continue` ;
> echo "$content" | tail -n +2 `#Print the content with out the first line (yes +2 is counter intuitive)` ;
> done;
> >&2 echo `#Finally break the line of dots` ;
> ) | cut -d '-' -f 1 | sort --version-sort | uniq;
...
2
2.6
2.6.17
2.8
2.8.6
2.8.7
2.8.8
2.8.9
2.8.10
2.8.11
2.8.12
2.8.13
2.8.14
2.8.15
2.8.16
2.8.17
2.8.18
2.8.19
2.8.20
2.8.21
2.8.22
2.8.23
3
3.0
3.0.0
3.0.1
3.0.2
3.0.3
3.0.4
3.0.5
3.0.6
3.0.7
3.0.504
3.2
3.2.0
3.2.1
3.2.2
3.2.3
3.2.4
3.2.5
3.2.6
3.2.7
3.2.8
3.2.9
3.2.10
3.2.11
3.2.100
4
4.0
4.0.0
4.0.1
4.0.2
4.0.4
4.0.5
4.0.6
4.0.7
4.0.8
32bit
alpine
latest
nanoserver
windowsservercore
如果你想要bash_profile版本：
function docker-tags () {
name=$1
# Initial URL
url=https://registry.hub.docker.com/v2/repositories/library/$name/tags/?page_size=100
(
# Keep looping until the variable URL is empty
while [ ! -z $url ]; do
# Every iteration of the loop prints out a single dot to show progress as it got through all the pages (this is inline dot)
>&2 echo -n "."
# Curl the URL and pipe the output to Python. Python will parse the JSON and print the very first line as the next URL (it will leave it blank if there are no more pages)
# then continue to loop over the results extracting only the name; all will be stored in a variable called content
content=$(curl -s $url | python -c 'import sys, json; data = json.load(sys.stdin); print(data.get("next", "") or ""); print("
".join([x["name"] for x in data["results"]]))')
# Let's get the first line of content which contains the next URL for the loop to continue
url=$(echo "$content" | head -n 1)
# Print the content without the first line (yes +2 is counter intuitive)
echo "$content" | tail -n +2
done;
# Finally break the line of dots
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