在使用数据协定序列化程序序列化IXmlSerializable对象时，如何控制根元素名称空间和名称？

Question

我有一个实现IXmlSerializable的类型，我用DataContractSerializer序列化。在将其作为XML文档的根元素序列化时，如何控制根元素名称空间和名称？

说我有以下类型：

public partial class PersonDTO : IXmlSerializable
{
    public string Name { get; set; }

    #region IXmlSerializable Members

    public System.Xml.Schema.XmlSchema GetSchema()
    {
        return null;
    }

    public void ReadXml(System.Xml.XmlReader reader)
    {
        Name = reader["name"];
        if (!reader.IsEmptyElement)
            reader.Skip();
        reader.Read();
    }

    public void WriteXml(System.Xml.XmlWriter writer)
    {
        writer.WriteAttributeString("name", Name);
    }

    #endregion
}

如果我用DataContractSerializer作为我的根对象来序列化这个，我得到：

<PersonDTO name="John Doe" xmlns="http://schemas.datacontract.org/2004/07/MyClrNamespace" />

我希望根名称为<Person>，根名称空间为"http://www.MyCompany.com"，所以我尝试添加[DataContract]，如下所示：

[DataContract(Name = "Person", Namespace = "http://www.MyCompany.com")]
public partial class PersonDTO : IXmlSerializable
{
}

但是当我这样做时，DataContractSerializer抛出一个异常，说明类型'PersonDTO'不能是IXmlSerializable并且具有DataContractAttribute属性：

System.Runtime.Serialization.InvalidDataContractException occurred
  Message="Type 'PersonDTO' cannot be IXmlSerializable and have DataContractAttribute attribute."
  Source="System.Runtime.Serialization"
  StackTrace:
       at System.Runtime.Serialization.XmlDataContract.XmlDataContractCriticalHelper..ctor(Type type)
       at System.Runtime.Serialization.XmlDataContract..ctor(Type type)
       at System.Runtime.Serialization.DataContract.DataContractCriticalHelper.CreateDataContract(Int32 id, RuntimeTypeHandle typeHandle, Type type)
       at System.Runtime.Serialization.DataContract.DataContractCriticalHelper.GetDataContractSkipValidation(Int32 id, RuntimeTypeHandle typeHandle, Type type)
       at System.Runtime.Serialization.DataContract.GetDataContract(RuntimeTypeHandle typeHandle, Type type, SerializationMode mode)
       at System.Runtime.Serialization.DataContractSerializer.get_RootContract()

我知道在手动序列化时可以使用DataContractSerializer(Type type, String rootName, String rootNamespace)构造函数修改根名称和命名空间：

var person = new PersonDTO { Name = "John Doe", };

var serializer = new DataContractSerializer(typeof(PersonDTO), "Person", @"http://www.MyCompany.com");
var sb = new StringBuilder();
using (var textWriter = new StringWriter(sb))
using (var xmlWriter = XmlWriter.Create(textWriter))
{
    serializer.WriteObject(xmlWriter, person);
}
Console.WriteLine(sb);
// Outputs <Person name="John Doe" xmlns="http://www.MyCompany.com" />

但有没有办法通过属性自动执行此操作？