django-URL反向解析Reverse

Posted 2021-03-24 xiximayou

解决path中带参数的路径。

reverse(viewname,urlconf=None,args=None,Kwargs=None,current_app=None)

book/views.py

from django.http import HttpResponse
from django.shortcuts import render,redirect,reverse

# Create your views here.
def index(request):
    username = request.GET.get("username")
    if username is not None:
        return HttpResponse("welcome!")
    else:
        return redirect(reverse(‘loose‘,kwargs={‘a‘:100,‘b‘:200}))

def error(request,a,b):
    sum=a+b
    return HttpResponse("<h1>sum:{}</h1>".format(sum))

book/urls.py

from django.urls import path
from . import views

urlpatterns = [
    path(‘‘, views.index,name=‘index‘),
    path(‘error/<int:a>/<int:b>‘, views.error,name=‘loose‘),
]

大体过程：启动服务器后会调用views中index函数，由于没有username参数，会重定向到loose（views.error的命名空间），即会调用error函数，此时有两个参数a,b，需要通过reverse才能够传下去。