取url地址参数

Posted 2021-03-22 wangxiaoer5200

let url = ‘https://i-beta.cnblogs.com/posts/edit?param1=123&param2=second‘
let arr = url.split(‘&‘);

let obj = new Object();

for (var i = 0; i < arr.length; i++) {

  obj[arr[i].split(‘=‘)[0]] = arr[i].split(‘=‘)[1];

   }

 

执行后这里的obj = {param:‘123‘,
param2:‘second‘}