内连接+计数+分组依据

Posted 2021-03-19

我无法计算/分组内部联接的结果

我有两张桌子

1. results_dump：有两列：email和result（结果值可以是open或bounce）
2. all_data：有三列：email，full_name和address

第一个目标是查询result_dump表，并对特定"open"的结果为email的次数进行计数和分组。

此查询效果很好：

SELECT `email`, COUNT(*) AS count
FROM `result_dump`
WHERE `date` = "open" 
GROUP BY `email`
HAVING COUNT(*) > 3
ORDER BY count DESC

它取得这些结果的第二个目标（任何“打开”超过3次的人）并提取'full_name'和'地址'，这样我就会详细了解谁开了3次以上的电子邮件。

我有这个问题，它可以将数据汇集在一起​​ - 但我无法弄清楚如何让COUNT，HAVING和ORDER与INNER JOIN一起工作？

SELECT *
FROM all_data
INNER JOIN result_dump ON 
all_data.email = result_dump.email
where `result` = "open" 

答案

SELECT email,name,count(*)
FROM all_data
INNER JOIN result_dump ON 
all_data.email = result_dump.email
where `result` = "open" 
group by result_dump.email
having count(*)>3
ORDER by count DESC

我认为这个没有错。

另一答案

尝试使用以下查询：

SELECT * FROM all_data AS a
INNER JOIN 
(SELECT * FROM result_dump where email IN 
                                    (SELECT `email`
                                     FROM `result_dump`
                                     WHERE `date` = "open" 
                                     GROUP BY `email`
                                     HAVING count(email) >3
                                     ORDER BY count(email) DESC)) AS b
ON a.email = b.email
WHERE b.`result` = "open" 

另一答案

这很好......试试这个......

SELECT title.title，count（*），title.production_year，title.id as movie_id，title.flag as language，movie_info.info from title INNER JOIN movie_info ON title.id = movie_info.movi​​e_id;