我想通过电子邮件，年份和学期（学期）从数据库中检索数据。

Posted 2021-03-19

我想通过电子邮件来检索当前用户的考勤情况，具体如下 出席情况 表。接下来，我必须要精确地检索哪一年和哪一学期的出勤率，所以我试着在控制器中输入 "Date "作为参数，在服务中，但它没有帮助。它给了我下一个参数

Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'attendanceRepository': Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Failed to create query for method public abstract java.util.List com.example.demo.Repositories.AttendanceRepository.findAttendanceByEmail(java.lang.String,java.lang.String)! At least 2 parameter(s) provided but only 1 parameter(s) present in query.
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1796) ~[spring-beans-5.2.5.RELEASE.jar:5.2.5.RELEASE]
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:595) ~[spring-beans-5.2.5.RELEASE.jar:5.2.5.RELEASE]
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:517) ~[spring-beans-5.2.5.RELEASE.jar:5.2.5.RELEASE]
    at org.springframework.beans.factory.support.AbstractBeanFactory.lambda$doGetBean$0(AbstractBeanFactory.java:323) ~[spring-beans-5.2.5.RELEASE.jar:5.2.5.RELEASE]
    at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) ~[spring-beans-5.2.5.RELEASE.jar:5.2.5.RELEASE]
    at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:321) ~[spring-beans-5.2.5.RELEASE.jar:5.2.5.RELEASE]
    at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:202) ~[spring-beans-5.2.5.RELEASE.jar:5.2.5.RELEASE]
    at org.springframework.beans.factory.config.DependencyDescriptor.resolveCandidate(DependencyDescriptor.java:276) ~[spring-beans-5.2.5.RELEASE.jar:5.2.5.RELEASE]
    at org.springframework.beans.factory.support.DefaultListableBeanFactory.doResolveDependency(DefaultListableBeanFactory.java:1290) ~[spring-beans-5.2.5.RELEASE.jar:5.2.5.RELEASE]
    at org.springframework.beans.factory.support.DefaultListableBeanFactory.resolveDependency(DefaultListableBeanFactory.java:1210) ~[spring-beans-5.2.5.RELEASE.jar:5.2.5.RELEASE]
    at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:640) ~[spring-beans-5.2.5.RELEASE.jar:5.2.5.RELEASE]
    ... 32 common frames omitted

我也试过不使用参数，这是我的代码。

AttendanceController.java

@Autowired
    AttendanceService attendanceService;

    // Get User Attendance
    @RequestMapping(value = "/attendance", method = RequestMethod.GET)
    public List<Attendance> getUserAttendance(@AuthenticationPrincipal MyUserDetails myUserDetails, java.util.Date date) {
        return attendanceService.getUserAttendanceByEmail(myUserDetails.getEmail(), date);
    }

考勤记录库.java

public interface AttendanceRepository extends JpaRepository<Attendance, Integer> {
    List<Attendance> findAttendanceByEmail(String email, String year_and_term);
}

考勤服务.java

@Autowired
    AttendanceRepository attendanceRepository;

    // Finds in attendance table by email of the current user
    public List<Attendance> getUserAttendanceByEmail(String email, Date date) {
        Calendar cal = Calendar.getInstance();
        cal.setTime(date);

        int year = cal.get(Calendar.YEAR);
        int term = cal.get(Calendar.MONTH);

        if (term >= 1 && term <= 5)
            term = 1;
        else if (term >= 9 && term <= 12)
            term = 2;

        String year_and_term = year + "-" + (year+1) + " (" + term + ")";
        System.out.println(year_and_term);
        return attendanceRepository.findAttendanceByEmail(email, year_and_term);
    }

AttendanceEntity.java

@Entity
@Table(name = "attendance")
public class Attendance {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Integer id;
    @ManyToOne
    @JoinColumn(name="subject_id", nullable=false)
    private Subjects subjects;
    private String email;
    private Integer absent;
    private Integer attend;
    private Integer permitted;
    private String year_and_term;

    public Attendance(Integer id, Subjects subjects, String email, Integer absent, Integer attend, Integer permitted, String year_and_term) {
        this.id = id;
        this.subjects = subjects;
        this.email = email;
        this.absent = absent;
        this.attend = attend;
        this.permitted = permitted;
        this.year_and_term = year_and_term;
    }

    public Attendance() {
    }
    // getters and setters..

这是我的桌子 出席情况 在数据库中。

+----+------------+--------+--------+--------+-----------+---------------+
| id | subject_id | email  | absent | attend | permitted | year_and_term |
+----+------------+--------+--------+--------+-----------+---------------+
|  1 |          1 | damir  |      1 |      1 |         1 | 2019-2020 (2) |
|  2 |          2 | damir  |      0 |      5 |         2 | 2019-2020 (2) |
|  3 |          3 | rapkat |      0 |     10 |         0 | 2019-2020 (2) |
|  4 |          1 | damir  |     10 |     20 |         5 | 2019-2020 (1) |
|  5 |          2 | damir  |      2 |     20 |         0 | 2019-2020 (1) |
+----+------------+--------+--------+--------+-----------+---------------+

答案

其实你有两个问题，第一个问题是你在变量名year_and_term中加入了spring jpa关键字，即 "and"，你把这两个不同的值互相关联，可能将来你需要分别查询year和sem，那你就麻烦了。

所以现在你有两个解决方案：-

1. 如果你仍然想使用clubbed，那么请重构变量名，如yearNterm，即用N或其他你想要的东西代替and。

   List findByEmailAndYearNterm(String email, String year_and_term);

2. 或者你可以用我的方法，即把2个变量分开，比如1是年份，2是期限，那么你的查询就会像:-。

   List findByEmailAndYearAndTerm(String email, String year, String term)。

另一答案

你想获得基于两个字段的数据，但只传递一个字段。因此，为了使它工作，请做以下修改。

1. 始终使用骆驼大小写变量名（标准做法）year_and_term - yearAndTerm。

2. 用其他东西重命名字段，因为它可能会在jpa查询中产生一些问题（and是一个关键字）。

3. 将方法调用改为

   findAttendanceByEmailAndYearAndTerm。