线段树(Segment Tree)
Posted ranbom
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建立线段树
void build_tree(int arr[],int tree[],int node,int start,int end){ if(start==end){ tree[node] = arr[start];//叶子节点 } else{ int mid = (start + end)/2; int left_node = 2*node + 1; int right_node = 2*node + 2; build_tree( arr, tree, left_node, start, mid);//递归建左子树 build_tree( arr, tree, right_node, mid+1, end);//递归建右子树 tree[node] = tree[left_node] + tree[right_node];//维护 } }
更新某元素
void update_tree(int arr[],int tree[],int node, int start, int end,int idx, int val){ if(start == end){ arr[idx] = val; tree[node] = val; } else{ int mid = (start + end)/2; int left_node = 2*node +1; int right_node = 2*node +2; if(idx >= start &&idx <= mid){ update_tree( arr, tree, left_node, start, mid, idx, val); } else{ update_tree( arr, tree, right_node, mid+1, end, idx, val); } tree[node] = tree[left_node]+tree[right_node]; } }
查询区间和
int query_tree(int arr[], int tree[], int node, int start, int end, int L, int R){ if(R<start||L>end){ return 0; }else if(start == end||start>=L&&end<=R){//这里如果没有后面的,则每次查询都会一直递归到叶子节点,降低效率 return tree[node]; } else{ int mid = (start+end)/2; int left_node = 2*node + 1; int right_node = 2*node+2; int sum_left = query_tree( arr, tree, left_node, start, mid, L, R); int sum_right = query_tree( arr, tree, right_node, mid+1, end, L, R); return sum_left+sum_right; }
区间操作(加法)
void plus_tree(int arr[],int tree[],ll node,ll start,ll end,ll L,ll R,ll num){ if(start == end){ tree[node] += num; } else { int mid = (start+end)/2; int left_node = 2*node+1; int right_node = 2*node+2; if(L<=mid){ plus_tree(arr, tree, left_node, start, mid, L, R, num); } if (R>=mid+1){ plus_tree(arr, tree, right_node, mid+1, end, L, R, num); } tree[node] = tree[left_node]+tree[right_node]; } }
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