PAT Advanced 1031 Hello World for U (20分)
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Given any string of N (≥) characters, you are asked to form the characters into the shape of U
. For example, helloworld
can be printed as:
h d
e l
l r
lowo
That is, the characters must be printed in the original order, starting top-down from the left vertical line with n?1?? characters, then left to right along the bottom line with n?2?? characters, and finally bottom-up along the vertical line with n?3?? characters. And more, we would like U
to be as squared as possible -- that is, it must be satisfied that n?1??=n?3??=max { k | k≤n?2?? for all 3 } with n?1??+n?2??+n?3??−2=N.
Input Specification:
Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.
Output Specification:
For each test case, print the input string in the shape of U as specified in the description.
Sample Input:
helloworld!
Sample Output:
h !
e d
l l
lowor
这道题目考察了格式化字串,我们需要先补2个位置,除以三,进行计算两边的数量,最后再计算中间的
#include <iostream> using namespace std; int main() { string str; getline(cin, str); int row, N = str.length(), recol; row = (N + 2) / 3 ; recol = (N + 2) / 3 + (N + 2) % 3 - 2; for(int i = 0; i < row; i++){ cout << str[i]; for(int j = 0; j < recol; j++) if(i != row - 1) cout << " "; else cout << str[j + row]; cout << str[N - i -1] << endl; } return 0; }
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