CF1B-Spreadsheets

Posted 2021-03-13 ac-ac

CF1B-Spreadsheets

1. 题意：26进制与10进制的转换

2. 代码实现：

   #include<bits/stdc++.h>
   using namespace std;
   int main(void){
       int t;
       cin >> t;
       while(t--){
           string s;
           cin >> s;
           int len = s.size();
           bool flag = 0;//flag 用来标志哪种串
           for(int i = len-1; i >= 0; i--){
               if(isalpha(s[i])&&isdigit(s[i-1])&&isdigit(s[i+1])){
                   flag = 1;
                   break;
               }
           }
           if(flag){//是R---C---
               int sum1 = 0;
               int i;
               for(i = 1; isdigit(s[i]); i++){
                   sum1 = sum1*10+(s[i]-'0');
               }
               int sum2 = 0;
               for(i = i+1; i < len; i++){
                   sum2 = sum2*10+(s[i]-'0');
               } // 取出数字
               stack<char> st;
               while(sum2){    
                   int t = sum2%26;
                   if(t==0){         //特别注意Z这种情况
                       st.push('Z');
                       sum2--;
                   }
                   else
                       st.push(t-1+'A');
                   sum2 /= 26;
               }   
               while(!st.empty()){
                   cout<<st.top();
                   st.pop();
               }
               cout<<sum1<<endl;
           }else{
               int sum1 = 0;
               int i;
               for(i = 0; isalpha(s[i]); i++){
                   sum1 = sum1*26 + (s[i]-'A'+1);
               }
               int sum2 = 0;
               for(i; i < len; i++){
                   sum2 = sum2*10+(s[i]-'0');
               }
               cout<<'R'<<sum2<<'C'<<sum1<<endl;
           }
       }
       return 0;
   }