从字符串中获取时间格式的字符

Posted 2021-03-11 ittt

const list = ‘ddsadsd2012-02-09 19:00‘

for (let i = 0; i < list.length; i++) {
    let str = list[i].workContent
    console.log(‘str‘,str)
    let datetime = [], date;
    str.replace(/((d{4}(-d{1,2}){2}).{2})?(d{1,2}(:d{1,2}){2})/g, function ($0, $1, $2, $3, $4) {
        if ($2 && $2 !== date) date = $2;
        datetime.push($1+$4);
    })
    list[i].time=datetime[0]?datetime[0]:‘‘
    console.log(‘time‘,datetime.join(‘
‘))
}