P5840 [COCI2015]Divljak
Posted isaunoya
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了P5840 [COCI2015]Divljak相关的知识,希望对你有一定的参考价值。
// powered by c++11
// by Isaunoya
#include <bits/stdc++.h>
#define rep(i, x, y) for (register int i = (x); i <= (y); ++i)
#define Rep(i, x, y) for (register int i = (x); i >= (y); --i)
using namespace std;
using db = double;
using ll = long long;
using uint = unsigned int;
#define int long long
using pii = pair<int, int>;
#define ve vector
#define Tp template
#define all(v) v.begin(), v.end()
#define sz(v) ((int)v.size())
#define pb emplace_back
#define fir first
#define sec second
// the cmin && cmax
Tp<class T> void cmax(T& x, const T& y) {
if (x < y) x = y;
}
Tp<class T> void cmin(T& x, const T& y) {
if (x > y) x = y;
}
// sort , unique , reverse
Tp<class T> void sort(ve<T>& v) { sort(all(v)); }
Tp<class T> void unique(ve<T>& v) {
sort(all(v));
v.erase(unique(all(v)), v.end());
}
Tp<class T> void reverse(ve<T>& v) { reverse(all(v)); }
const int SZ = 0x191981;
struct FILEIN {
~FILEIN() {}
char qwq[SZ], *S = qwq, *T = qwq, ch;
char GETC() { return (S == T) && (T = (S = qwq) + fread(qwq, 1, SZ, stdin), S == T) ? EOF : *S++; }
FILEIN& operator>>(char& c) {
while (isspace(c = GETC()))
;
return *this;
}
FILEIN& operator>>(string& s) {
while (isspace(ch = GETC()))
;
s = ch;
while (!isspace(ch = GETC())) s += ch;
return *this;
}
Tp<class T> void read(T& x) {
bool sign = 1;
while ((ch = GETC()) < 0x30)
if (ch == 0x2d) sign = 0;
x = (ch ^ 0x30);
while ((ch = GETC()) > 0x2f) x = x * 0xa + (ch ^ 0x30);
x = sign ? x : -x;
}
FILEIN& operator>>(int& x) { return read(x), *this; }
FILEIN& operator>>(signed& x) { return read(x), *this; }
FILEIN& operator>>(unsigned& x) { return read(x), *this; }
} in;
struct FILEOUT {
const static int LIMIT = 0x114514;
char quq[SZ], ST[0x114];
signed sz, O;
~FILEOUT() { flush(); }
void flush() {
fwrite(quq, 1, O, stdout);
fflush(stdout);
O = 0;
}
FILEOUT& operator<<(char c) { return quq[O++] = c, *this; }
FILEOUT& operator<<(string str) {
if (O > LIMIT) flush();
for (char c : str) quq[O++] = c;
return *this;
}
Tp<class T> void write(T x) {
if (O > LIMIT) flush();
if (x < 0) {
quq[O++] = 0x2d;
x = -x;
}
do {
ST[++sz] = x % 0xa ^ 0x30;
x /= 0xa;
} while (x);
while (sz) quq[O++] = ST[sz--];
return;
}
FILEOUT& operator<<(int x) { return write(x), *this; }
FILEOUT& operator<<(signed x) { return write(x), *this; }
FILEOUT& operator<<(unsigned x) { return write(x), *this; }
} out;
int n, q;
const int maxn = 2e6 + 62;
int ch[maxn][26], cnt = 1, ed[maxn], fail[maxn];
int ins(string s) {
int p = 1;
for (char c : s) {
int x = c - 'a';
if (!ch[p][x]) ch[p][x] = ++cnt;
p = ch[p][x];
}
return p;
}
void buildfail() {
queue<int> q;
for (int i = 0; i < 26; i++)
if (ch[1][i])
fail[ch[1][i]] = 1, q.push(ch[1][i]);
else
ch[1][i] = 1;
while (!q.empty()) {
int u = q.front();
q.pop();
for (int i = 0; i < 26; i++)
if (ch[u][i])
fail[ch[u][i]] = ch[fail[u]][i], q.push(ch[u][i]);
else
ch[u][i] = ch[fail[u]][i];
}
}
vector<int> g[maxn];
int sz[maxn], d[maxn], son[maxn];
void dfs(int u) {
sz[u] = 1;
for (int v : g[u]) {
d[v] = d[u] + 1;
dfs(v), sz[u] += sz[v];
if (sz[v] > sz[son[u]]) son[u] = v;
}
}
int dfn[maxn], idx = 0, top[maxn];
void dfs(int u, int t) {
top[u] = t, dfn[u] = ++idx;
if (son[u]) dfs(son[u], t);
for (int v : g[u])
if (v ^ son[u]) dfs(v , v);
}
int lca(int u, int v) {
while (top[u] ^ top[v]) {
if (d[top[u]] < d[top[v]]) u ^= v ^= u ^= v;
u = fail[top[u]];
// fa_u = fail_u
}
return d[u] < d[v] ? u : v;
}
// bit
int c[maxn];
int low(int x) { return x & -x; }
void upd(int x, int y) {
for (; x <= cnt; x += low(x)) c[x] += y;
}
int qry(int x) {
int ans = 0;
for (; x; x ^= low(x)) ans += c[x];
return ans;
}
signed main() {
#ifdef _WIN64
freopen("testdata.in", "r", stdin);
#else
ios_base ::sync_with_stdio(false);
cin.tie(nullptr), cout.tie(nullptr);
#endif
// code begin.
in >> n;
rep(i, 1, n) {
string s;
ed[i] = ins((in >> s, s));
}
buildfail();
rep(i, 2, cnt) g[fail[i]].pb(i);
dfs(1), dfs(1, 1);
in >> q;
while (q--) {
int op;
in >> op;
if (op == 1) {
string s;
in >> s;
int p = 1;
vector<int> P;
for (char c : s) {
int x = c - 'a';
p = ch[p][x], P.pb(p);
}
sort(P.begin() , P.end() , [](int x, int y) { return dfn[x] < dfn[y]; });
P.erase(unique(P.begin() , P.end()) , P.end()) ;
for (int i = 0; i < sz(P); i++) {
upd(dfn[P[i]], 1);
if (i) upd(dfn[lca(P[i - 1] , P[i])], -1);
}
} else {
int x;
out << (in >> x , qry(dfn[ed[x]] + sz[ed[x]] - 1) - qry(dfn[ed[x]] - 1)) << '
' ;
}
}
return 0;
// code end.
}
以上是关于P5840 [COCI2015]Divljak的主要内容,如果未能解决你的问题,请参考以下文章
bzoj 3881 [Coci2015]Divljak——LCT维护parent树链并