拼写单词

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/*给你一份『词汇表』(字符串数组) words 和一张『字母表』(字符串) chars。
假如你可以用 chars 中的『字母』(字符)拼写出 words 中的某个『单词』(字符串),那么我们就认为你掌握了这个单词。
注意:每次拼写时,chars 中的每个字母都只能用一次。
返回词汇表 words 中你掌握的所有单词的 长度之和。
示例 1:
输入:words = ["cat","bt","hat","tree"], chars = "atach"
输出:6
解释:
可以形成字符串 "cat" 和 "hat",所以答案是 3 + 3 = 6。
示例 2:
输入:words = ["hello","world","leetcode"], chars = "welldonehoneyr"
输出:10
解释:
可以形成字符串 "hello" 和 "world",所以答案是 5 + 5 = 10。
链接:https://leetcode-cn.com/problems/find-words-that-can-be-formed-by-characters*/

public static int countCharacters(String[] words, String chars) {
int result = 0;
int[] a = new int[26];
char[] chars1 = chars.toCharArray();
for (int i = 0; i < chars1.length; i++) {
a[chars1[i]-‘a‘] += 1;
}
for(int j = 0 ; j<words.length ;j++){
char[] word = words[j].toCharArray();
int[] b = new int[26];
for (int i = 0; i < word.length; i++) {
b[word[i]-‘a‘] += 1;
}
boolean flag = true;
for (int i = 0; i <26 ; i++) {
if(b[i] > a[i]){
flag = false;
break;
}
}
if(flag) result += word.length;
}

return result;
}

public static void main(String[] args) {
String[] words = {"cat","bt","hat","tree"};
String chars = "atach";

String[] b = {"dyiclysmffuhibgfvapygkorkqllqlvokosagyelotobicwcmebnpznjbirzrzsrtzjxhsfpiwyfhzyonmuabtlwin","ndqeyhhcquplmznwslewjzuyfgklssvkqxmqjpwhrshycmvrb","ulrrbpspyudncdlbkxkrqpivfftrggemkpyjl","boygirdlggnh","xmqohbyqwagkjzpyawsydmdaattthmuvjbzwpyopyafphx","nulvimegcsiwvhwuiyednoxpugfeimnnyeoczuzxgxbqjvegcxeqnjbwnbvowastqhojepisusvsidhqmszbrnynkyop","hiefuovybkpgzygprmndrkyspoiyapdwkxebgsmodhzpx","juldqdzeskpffaoqcyyxiqqowsalqumddcufhouhrskozhlmobiwzxnhdkidr","lnnvsdcrvzfmrvurucrzlfyigcycffpiuoo","oxgaskztzroxuntiwlfyufddl","tfspedteabxatkaypitjfkhkkigdwdkctqbczcugripkgcyfezpuklfqfcsccboarbfbjfrkxp","qnagrpfzlyrouolqquytwnwnsqnmuzphne","eeilfdaookieawrrbvtnqfzcricvhpiv","sisvsjzyrbdsjcwwygdnxcjhzhsxhpceqz","yhouqhjevqxtecomahbwoptzlkyvjexhzcbccusbjjdgcfzlkoqwiwue","hwxxighzvceaplsycajkhynkhzkwkouszwaiuzqcleyflqrxgjsvlegvupzqijbornbfwpefhxekgpuvgiyeudhncv","cpwcjwgbcquirnsazumgjjcltitmeyfaudbnbqhflvecjsupjmgwfbjo","teyygdmmyadppuopvqdodaczob","qaeowuwqsqffvibrtxnjnzvzuuonrkwpysyxvkijemmpdmtnqxwekbpfzs","qqxpxpmemkldghbmbyxpkwgkaykaerhmwwjonrhcsubchs"};
String a = "usdruypficfbpfbivlrhutcgvyjenlxzeovdyjtgvvfdjzcmikjraspdfp";
int i = countCharacters(b, a);
System.out.println("args = " + i);
}

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