北京理工大学复试上机--2012

Posted 2021-03-03 ache

1、输入十个正整数数字从小到大排序

输入:1 2 5 7 9 10 45 67 24 26

输出:1,2,5,7,9,10,24,26,45,67

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int main()
{
    int a, i;
    vector<int> v;
    for (i = 0; i < 10; i++)
    {
        scanf("%d", &a);
        v.push_back(a);
    }
    sort(v.begin(), v.end());
    for (i = 0; i < 10; i++)
    {
        cout << v[i];
        if (i < 9)
            cout << ",";
    }
    return 0;
}

2、学生有(学号，姓名，性别，年龄)，初始化三个学生的信息

(10, wes, f, 23) (20, ert, f, 45) (30, str, t, 89) ,然后对学生信息进行插入和删

除处理

例如: I12,rt, f, 67表示插入12,rt, f, 67

D10表示删除学号为10的学生的信息

每次操作完成以后输出所有学生的信息按学号从大到小排序

输入: I12,rt,f,67

输出: (30,str,t,89),(20,erf,f,45),(12,rt,f,67),(10,wes,f,23)

输入: D10

输出: (30,str,t,89),(20,erf,f,45),(12,rt,f,67)

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;

struct student
{
    int age, id;
    string name, gender;
};

bool cmp(student t1, student t2)
{
    if (t1.id != t2.id)
        return t1.id > t2.id;
}

int main()
{
    int a, i, j;
    string s;
    student stu;
    vector<student> v;
    student st[3];
    st[0].id = 10; st[0].name = "wes"; st[0].gender = "f"; st[0].age = 23;
    st[1].id = 20; st[1].name = "erf"; st[1].gender = "f"; st[1].age = 45;
    st[2].id = 30; st[2].name = "str"; st[2].gender = "t"; st[2].age = 89;
    v.push_back(st[0]);
    v.push_back(st[1]);
    v.push_back(st[2]);
    while (getline(cin, s)) {
        string str[4];
        if (s[0] == ‘I‘) {
            int n = (s[1] - ‘0‘) * 10 + (s[2] - ‘0‘);
            stu.id = n;
            n = s[s.length() - 1] - ‘0‘ + (s[s.length() - 2] - ‘0‘) * 10;
            stu.age = n;
            string ss = "";
            for (i = 4; i < s.length(); i++) {
                if (s[i] == ‘,‘) {
                    stu.name = ss;
                    ss = "";
                    break;
                }
                ss += s[i];
            }
            for (j = i + 1; j < s.length(); j++) {
                if (s[j] == ‘,‘) {
                    stu.gender = ss;
                    break;
                }
                ss += s[j];
            }
            v.push_back(stu);
            sort(v.begin(), v.end(), cmp);
            for (i = 0; i < v.size(); i++) {
                cout << "(" << v[i].id << "," << v[i].name << "," << v[i].gender << "," << v[i].age << ")";
                if (i < v.size() - 1)
                    cout << ",";
            }
        }
        if (s[0] == ‘D‘) {
            int n = (s[1] - ‘0‘) * 10 + (s[2] - ‘0‘);
            for (i = 0; i < v.size(); i++) {
                if (v[i].id == n)
                {
                    v.erase(v.begin() + i);
                    break;
                }
            }
            sort(v.begin(), v.end(), cmp);
            for (i = 0; i < v.size(); i++) {
                cout << "(" << v[i].id << "," << v[i].name << "," << v[i].gender << "," << v[i].age << ")";
                if (i < v.size() - 1)
                    cout << ",";
            }
        }
    }

    return 0;
}

3、利用后序和中序确定前序遍历结果

示例:

输入(按后序、中序): CHBEDA CBHADE

输出: ABCHDE

 

这个题目前还没完全搞清楚，先空着

 

 

PS：突入其来的又不会的题，甚是心慌！！！  要踏实一点了，加油！