练习文件拷贝——利用文件流实现文件的复制

Posted 2021-03-03 qiaoxin11

 1 import java.io.*;
 2 
 3 public class FileCopy {
 4     public static void main(String[] args) {
 5         Copy("女子.jpg", "漂亮.jpg");
 6     }
 7     public static void Copy(String srcPath, String destPath) {
 8         //1、创建源
 9         File src = new File(srcPath);  //源头
10         File dest = new File(destPath); //目的地
11         //2、选择流
12         InputStream inputStream = null;
13         OutputStream outputStream = null;
14         try {
15             inputStream = new FileInputStream(src);
16             outputStream = new FileOutputStream(dest);
17             //3、操作流（分段读取）
18             byte[] flush = new byte[1024]; //缓冲容器
19             int len = -1;//接收长度
20             while ((len = inputStream.read(flush)) != -1) {
21                 outputStream.write(flush, 0, len);
22             }
23             outputStream.flush();//刷新此输出流并强制任何缓冲的输出字节被写出,细节
24         } catch (FileNotFoundException e) {
25             e.printStackTrace();
26         } catch (IOException e) {
27             e.printStackTrace();
28         } finally {
29             //4、释放资源，分别关闭，先打开的后关闭， 好处：只要保证我的目的地正确就可以
30             try {
31                 if (outputStream != null) {
32                     outputStream.close();
33                 }
34             } catch (IOException e) {
35                 e.printStackTrace();
36             }
37 
38             try {
39                 if (inputStream != null) {
40                     inputStream.close();
41                 }
42             } catch (IOException e) {
43                 e.printStackTrace();
44             }
45         }
46     }
47 }