Salary Changing CodeForces - 1251D (二分)

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Salary Changing

题意:

有n个员工,每个员工的薪资区间为[li , ri]

问员工薪资的中位数最大是多少。

思路:
二分答案,check()检查薪资 >= mid 的人数 >= n/2 + 1 则返回 true , 不然返回 false

技术图片
 1 #include<cstdio>
 2 #include<string.h>
 3 #include<algorithm>
 4 #include<cmath>
 5 #include<iostream>
 6 #include<vector>
 7 #include<queue>
 8 #include<set>
 9 #include<map>
10 #include<cctype>
11 #define ios ios::sync_with_stdio(false),cin.tie(0),cout.tie(0)
12 #define mem(a,x) memset(a,x,sizeof(a))
13 #define lson rt<<1,l,mid
14 #define rson rt<<1|1,mid + 1,r
15 #define P pair<int,int>
16 #define ull unsigned long long
17 using namespace std;
18 typedef long long ll;
19 const int maxn = 1e6 + 10;
20 const ll mod = 998244353;
21 const int inf = 0x3f3f3f3f;
22 const long long INF = 0x3f3f3f3f3f3f3f3f;
23 const double eps = 1e-7;
24 inline ll read()
25 {
26     ll X = 0, w = 0; char ch = 0;
27     while (!isdigit(ch)) { w |= ch == -; ch = getchar(); }
28     while (isdigit(ch)) X = (X << 3) + (X << 1) + (ch ^ 48), ch = getchar();
29     return w ? -X : X;
30 }
31 ll n, m, k;
32 ll cnt[maxn] = {0};
33 ll ou = 0, ji = 0;
34 vector<int>vec[maxn];
35 
36 int main()
37 {
38     n = read(), m = read();
39     int ans = min(n, m);
40     cout << ans + 1 << endl;
41     for (int i = 0; i <= ans; ++i)
42     {
43         cout << ans - i << " " << i << endl;
44     }
45     return 0;
46 }
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